Proving H as a Subgroup of G: Using the Abelian Property

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SUMMARY

The discussion focuses on proving that the set H, defined as H = {x ∈ G : x = x^{-1}}, is a subgroup of the abelian group G. Two methods are proposed for the proof: the first method requires demonstrating that if a, b are in H, then both a + b and -a are also in H; the second method focuses on showing that if a, b are in H, then a - b is in H. The key challenge identified is proving that ab = (ab)^{-1} using the abelian property of G.

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Homework Statement


G is an abelian group
Let [itex]H = {x \in G : x = x^{-1}[/itex]

Prove H is a subgroup of G.

I have two methods in my arsenal to do this (and I am writing them out additively just for ease):
1. Let a,b be in H. If a + b is in H AND -a is in H then H<G.
or
2.Let a,b be in H. if a-b is in H then H<G.

Solution:
If I use method one the 2nd part is given practically (if a is in H then a^-1 = a is certainly in H).

Then I need to show ab is in H. this is what I am struggling with... I feel (since it is given) I should use the fact that G is abelian but not sure where/how to do that!
 
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So you need to show that

[tex]ab=(ab)^{-1}[/tex]

First, write out what [itex](ab)^{-1}[/itex] is. Then us that a and b are in H.
 

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