Proving Inequality for Variables with Constraints

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SUMMARY

The discussion centers on proving the inequality $\sqrt{a(1-b)(1-c)} + \sqrt{b(1-a)(1-c)} + \sqrt{c(1-a)(1-b)} \le 1 + \sqrt{abc}$ for variables $a$, $b$, and $c$ constrained within the range $0 \le a, b, c \le 1$. A correction was made regarding the inequality sign, confirming that the correct form is indeed the one presented. Participants, including Albert and lfdahl, engaged in clarifying the proof and acknowledging typographical errors in the initial statements.

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lfdahl
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Let $0 \le a,b,c \le 1.$ Prove the inequality:$\sqrt{a(1-b)(1-c)}+ \sqrt{b(1-a)(1-c)}+\sqrt{c(1-a)(1-b)} \le 1 + \sqrt{abc}$
 
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lfdahl said:
Let $0 \le a,b,c \le 1.$ Prove the inequality:$\sqrt{a(1-b)(1-c)}+ \sqrt{b(1-a)(1-c)}+\sqrt{c(1-a)(1-b)} \ge 1 + \sqrt{abc}(1)$
for a=b=c=1 ,(1) is not true
 
Albert said:
for a=b=c=1 ,(1) is not true

You´re right, Albert. I´ve made a typo. The inequality sign should be reversed. I´m sorry for my mistake.

Thankyou for pointing this out to me.

Cheers, lfdahl
 
lfdahl said:
Let $0 \le a,b,c \le 1.$ Prove the inequality:$\sqrt{a(1-b)(1-c)}+ \sqrt{b(1-a)(1-c)}+\sqrt{c(1-a)(1-b)} \le 1 + \sqrt{abc}$
my solution:
$set:\,\, (1-a)=sin^2 A,(1-b)=sin^2 B, 1-c=sin^2C,it\,\,is\,\,to\,\,prove:\\
cosAsinBsinC+cosBsinCsinA+cosCsinAsinB-cosAcosBcosC\leq1\\
or\,\, cosA(sinBsinC-cosBcosC)+sinA(sinBcosC+cosBsinC)\leq 1\\
sinAsin(B+C)-cosAcos(B+C)\leq 1\\
cosAcos(B+C)-sinAsin(B+C)\geq -1\\
cos(A+B+C)\geq -1$
$and \,\, the\,\,proof\,\,is \,\, done $
 
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Albert said:
my solution:
$set:\,\, (1-a)=sin^2 A,(1-b)=sin^2 B, 1-c=sin^2C,it\,\,is\,\,to\,\,prove:\\
cosAsinBsinC+cosBsinCsinA+cosCsinAsinB-cosAcosBcosC\leq1\\
or\,\, cosA(sinBsinC-cosBcosC)+sinA(sinBcosC+cosBsinC)\leq 1\\
sinAsin(B+C)-cosAcos(B+C)\leq 1\\
cosAcos(B+C)-sinAsin(B+C)\geq -1\\
cos(A+B+C)\geq -1$
$and \,\, the\,\,proof\,\,is \,\, done $

Very nice solution, Albert! :cool:
 

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