Proving Infinite Limit using Delta-Epsilon: One More Limit Homework Statement

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Homework Help Overview

The discussion revolves around proving an infinite limit using the delta-epsilon definition, specifically for the limit of the function as x approaches 1 from the right.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of an infinite limit and question its correctness. There are attempts to clarify the limit expression and suggest taking the logarithm as a potential approach.

Discussion Status

Participants are actively discussing the correct interpretation of the limit and the appropriate definition to use. Some guidance has been provided regarding the definition of an infinite limit, but there is no explicit consensus on the approach to take.

Contextual Notes

There is some confusion regarding the limit expression, with participants clarifying the correct form of the limit as x approaches 1 from the right. The discussion includes verification of definitions and assumptions related to the problem.

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Homework Statement


lim as x goes to 1 from the right of 2^1/x-1=inf


Homework Equations



solve using delta-epsilon

The Attempt at a Solution



i am not sure how to prove an infinite limit, I have a defn that states, If for epsilon>0 there exists an M>0 such that x>M implies |f(x)-L|< epsilon. My main problem is that I am not sure how to do it, and how to get the power of two out of the way
 
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take the log
 
is the definition right?
 
did you mean lim x->1+ 2^(1/(1-x)) = 0?
 
Last edited:
no the problem says it goes to inf
 
Math_Geek said:
no the problem says it goes to inf

Oh it's lim x->1+ 2^(1/(x-1)), which is inf yea


The correct definition is

lim x->a+ f(x) = inf if for all M > 0 there is a d > 0 s.t. 0 < |x-1| < d and x > 1 implies |f(x)| > M
 

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