Proving Infinitely Many Natural Numbers: Larson 4.1.6

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Homework Help Overview

The discussion revolves around proving that there are infinitely many natural numbers \( a \) such that \( n^4 + a \) is not prime for any natural number \( n \). The problem is situated within number theory, particularly focusing on properties of prime numbers and factorization.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore various values for \( a \), such as \( a = 4 \) and \( a \) as a multiple of 5 minus 1, questioning their validity. There is an attempt to factor \( n^4 + a \) under certain conditions, with some participants expressing uncertainty about how to proceed. Others reference Fermat's Little Theorem and its implications for the problem.

Discussion Status

The discussion is ongoing, with participants sharing different ideas and approaches. Some have suggested identities that may be relevant, while others are still grappling with the initial steps of the problem. There is a mix of exploration and clarification happening, but no consensus has been reached yet.

Contextual Notes

Participants have noted the challenge of finding a suitable form for \( a \) that allows for factorization, and there is an acknowledgment of the need for a proof that holds for all natural numbers \( n \). The discussion reflects a variety of interpretations and methods being considered.

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[SOLVED] Larson 4.1.6

Homework Statement


Prove that there are infinitely many natural numbers a with the following property: The number n^4+a is not prime for any number n.

Homework Equations


The Attempt at a Solution


I cannot even think of one such natural number a. :(
I need to find some way to factor this after we put some restrictions on a. That is we need to express a in a special form that makes this factorable. If a is equal to b^4, it is not necessarily factorable. In fact, I don't know of any power of b that will make it factorable. a cannot be a function of n. I really don't know what to do.
 
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a=4
a=(multiple of 5)-1
hence infinite
i guess
correct me if iam wrong
have you any idea of fermat theorem
n^5-n is divisible by 5
can be prooved ,it is a simpler form of fermat theorem
n(n^4-1) certainly n^4 -1 is divisible by 5
add any multiple of 5 to it
you get
 
Fermat's Little Theorem says that if p is a prime number that does not divide an integer n, then n^{p-1} \equiv 1 \mod p.

Therefore that will only apply when n is not divisible by 5. We need a proof for all n in N.
 
Maybe you can use Sophie Germain's identity:
a^4 + 4 b^4 = (a^2 + 2 b^2 + 2 a b) (a^2 + 2 b^2 - 2 a b).
 
durt said:
Maybe you can use Sophie Germain's identity:
a^4 + 4 b^4 = (a^2 + 2 b^2 + 2 a b) (a^2 + 2 b^2 - 2 a b).

Wow. Thanks. I'm glad I posted this question because I never would have thought of that.
 

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