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Proving initial speed of a particle

  1. Feb 8, 2010 #1
    1. The problem statement, all variables and given/known data
    Particle A of mass 1kg is at rest 0.2m from the edge of a smooth horizontal table 0.8m high. It is connected by a light inextensible string of length 0.7m to particle B of mass 0.5kg. Particle B is initially at rest at the edge of table closest to A but then falls out. Assuming B's initial horizontal velocity is zero, prove that speed which A begins to move is 1.04m/s


    2. Relevant equations
    F = ma
    Momentums : m(v-u) etc.


    3. The attempt at a solution
    I solved it before, but I cant seem to remember how to =(
     
    Last edited: Feb 8, 2010
  2. jcsd
  3. Feb 8, 2010 #2
    do you know this equation:
    [tex]v^{2}=v^{2}_{0}+2gh[/tex]
    which can be derived from equation of motion in straight line with constant acceleration. You can use it to find speed of B at the moment when it starts to pull ball A. When you have this velocity, use conservation of momentum.
     
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