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## Homework Statement

Let G be a group acting on a set X, and let g in G. Show that a subset Y of X is invariant under the action of the subgroup <g> of G iff gY=Y. When Y is finite, show that assuming gY is a subset of Y is enough.

## Homework Equations

If Y is a subset of X, we write GY for the set { g·y : y Y and g G}. We call the subset Y invariant under G if GY = Y (which is equivalent to GY ⊆ Y)

## The Attempt at a Solution

gY=Y implies that gy is in Y for all g in G and y in Y. G is a group so all powers of G would be in G as well. so <g>Y=Y must be true also and Y is invariant under action of <g>. If Y was invariant under the action of <g> but gY=/=Y. This would mean that there exists some y' in Y such that gy =/= y' so the set <g>Y would not contain the element y' and <g>Y would not equal to Y which contradicts that Y is invariant. I'm also wondering how to proceed for finite case. Any help would be much appreciated; thanks.