Proving Irrationality of Sums and Products of Irrational Numbers

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Homework Help Overview

The discussion revolves around the properties of sums and products involving rational and irrational numbers. The original poster presents several questions regarding the irrationality of expressions formed by combining rational and irrational numbers.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the implications of combining rational and irrational numbers, questioning whether certain expressions remain irrational. They discuss specific cases and attempt to reason through contradictions based on definitions of rationality.

Discussion Status

Some participants have provided insights and reasoning for the first question, while others are exploring the implications of the second question. There is ongoing debate about the validity of assumptions and the conditions under which certain expressions can be rational or irrational. Multiple interpretations are being examined without a clear consensus.

Contextual Notes

Participants are grappling with the definitions of rational and irrational numbers and the conditions under which their combinations yield rational or irrational results. There is a noted confusion regarding the formulation of the second question and its implications.

hashimcom
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hi
i m hashim i want to solve a qquestion
1.if x is rational & y is irrational proof x+y is irrational?
2. if x not equal to zero...y irrational proof x\y is irrational??
3.if x,y is irrational ..dose it implise to x+y is irrational or x*y is irrational

thanks
please
hashim
 
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1. is easy, what have you tried so far?
2. Do you mean x/y? And is x supposed to be rational? If not then 2 is false.
 
1. since x rational we can write it as p/q, where they cannot be simplifyed anymore.
suppose now that x+y is rational,
so it also can be written like r/s, where r,s are integers
so x+y=r/s,

p/q +y=r/s , y=r/s -p/q, so we come to a contradiction, since the right hand of the equation is also a rational, but it contradicts the fact that y is irrational, so our first assumtion that x+y is rational is wrong.
 
3. for the it looks like trivial.
 
sutupidmath said:
3. for the it looks like trivial.

what it mean?
please

& where num 2 proof
please

hashim
thanks
 
well, i am not going to show u the whole proof for the last one. But try to reason the same way i did on problem 1.
 
mr sutupidmath ...
czn u say my proof for 2
pf:
since x non zerc, so x either rational or irrational
i. if x rational & x non zero...
x =p\q wher p,q is intger...
y is irrational.
now suppose x\y is rastional
x\y=r\s...r,s is integer.
x\y=(p\q)\y=r\s
y=(s\r)*(p\q)...which is rational...contradict
ii. x is irratinal, x non zero...y irrational
suppose x\y = r\s
x = r\s*y...how to continue now?

please help me?
thanks
hashim
 
The way you have stated it, "2. if x not equal to zero...y irrational proof x\y is irrational", it's NOT true! For example, [itex]\pi/\pi= 1[/itex]. The ratio of two irrational numbers certainly can be rational. You probably meant: If x is a rational number, not equal to 0, and y is irrational, then x/y is irrational. For all of these, you don't need to go back to the definition of rational numbers as m/n. Use the fact that the rational numberse are closed under the operations of addition, subtraction, multiplication, and division (with divisor not 0).
 
HallsofIvy said:
The way you have stated it, "2. if x not equal to zero...y irrational proof x\y is irrational", it's NOT true! For example, [itex]\pi/\pi= 1[/itex]. QUOTE]

what if we put it this way. x, y both irrational and x is not equal to y, then what could we say for x/y??
can we go this way, since x irrational it cannot be written as p/q, for the same reason y cannot be written as r/s, where r,s,p,q are all integers. then is it safe to reason this way

x/y cannot be equal to (p/q)/(r/s)= ps/qr whic is obviously rational, so we can conclude that x/y under these conditions is irrational right??
 
  • #10
sutupidmath said:
HallsofIvy said:
The way you have stated it, "2. if x not equal to zero...y irrational proof x\y is irrational", it's NOT true! For example, [itex]\pi/\pi= 1[/itex]. QUOTE]

what if we put it this way. x, y both irrational and x is not equal to y, then what could we say for x/y??
can we go this way, since x irrational it cannot be written as p/q, for the same reason y cannot be written as r/s, where r,s,p,q are all integers. then is it safe to reason this way

x/y cannot be equal to (p/q)/(r/s)= ps/qr whic is obviously rational, so we can conclude that x/y under these conditions is irrational right??

No, because you presupposed that line with x and y not being equal to (p/q) and (r/s) respectively, so obviouls they can't equal ps/qr. For a counter example consider [itex]5\pi/6\pi= 5/6[/itex]
 
  • #11
ok then, what could we say as a conclusion at this case. Because obviously we cannot conclude that at any case when x and y are irrational x/y is rational. FOr example, sqr3/sqr2 is irrational, or sqr6/sqr3, is obviously irrational.
 
  • #12
sutupidmath said:
ok then, what could we say as a conclusion at this case. Because obviously we cannot conclude that at any case when x and y are irrational x/y is rational. FOr example, sqr3/sqr2 is irrational, or sqr6/sqr3, is obviously irrational.

You can't say anything, sometimes it's rational, sometimes it isn't.
 

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