Proving L3 is a Lorentz Transformation

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SUMMARY

The discussion focuses on proving that the product of two Lorentz transformations, L1 and L2, results in another Lorentz transformation, L3. The key approach involves demonstrating the invariance of the spacetime interval under the transformation L3, expressed mathematically as gαβxαxβ = gμνΛμαΛνβxαxβ. The participants emphasize the importance of correctly applying indices and maintaining the structure of the transformations to validate that L3 retains the properties of Lorentz transformations.

PREREQUISITES
  • Understanding of Lorentz transformations in special relativity
  • Familiarity with Minkowski space and spacetime intervals
  • Knowledge of tensor notation and index manipulation
  • Basic concepts of metric tensors in physics
NEXT STEPS
  • Study the properties of Lorentz transformations in detail
  • Learn about Minkowski space and its implications in special relativity
  • Explore tensor calculus and index notation for advanced physics
  • Investigate the role of metric tensors in defining spacetime intervals
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This discussion is beneficial for physics students, particularly those studying special relativity, as well as educators and researchers interested in the mathematical foundations of Lorentz transformations.

martyf
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Homework Statement



L1 and L2 are two lorentz trasformation.
show that L3=L1 L2 is a lorentz trasformation too.


Homework Equations





The Attempt at a Solution

 
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I could be wrong but I think it would be enough to show the invariance of the dot product under L3.
 
what is the dot product?
 
The scalar product, or inner product or whatever it's called of 4-vectors. In Minkowski space it's r_1 \cdot r_2 = c^2 t_1 t_2 - x_1 x_2 - y_1 y_2 - z_1 z_1 or with the signs reversed depending on the convention. But if you haven't yet done the Minkowski notation then you could write L1 and L2 as Lorentz transformations with some velocities and show by applying them consecutively that L3 has the same form.
 
I write better :

I have: \Lambda ^{\mu}_{\nu} and \Lambda\widetilde{} ^{\mu}_{\nu} : lorentz trasformations.

Show that \Lambda\overline{} ^{\sigma}_{\rho} = \Lambda\widetilde{} ^{\sigma}_{\mu} \Lambda ^{\mu}_{\rho} is a lorentz trasformation
 
What is the definition of Lorentz transformation given in your notes and/or text?
 
a trasfonmation that not change the space-time distance of a point to the origin.
 
martyf said:
a trasfonmation that not change the space-time distance of a point to the origin.

Can you write a definition in terms of mathematics, i.e., \Lambda^\mu{}_\nu[/itex] is a Lorentz transformation iff ... ?
 
...if :

x^{2}_{0} - r ^{2}= (\Lambda ^{0}_{\nu} x_{0})^{2} -( \Lambda ^{\mu}_{\nu} r_{\mu})^{2}
 
  • #10
is it right?
 
  • #11
You don't have the indices right, your right hand side depends on on \nu whereas the left hand side doesn't. It should be:

(x^0)^2 - r^2 = (\Lambda^0{}_\nu x^\nu)^2 - (\Lambda^j{}_\nu x^\nu)^2

Where j goes from 1 to 3. More compactly:

g_\alpha_\beta x^\alpha x^\beta = g_\mu_\nu \Lambda^\mu{}_\alpha \Lambda^\nu{}_\beta x^\alpha x^\beta

Where g is the metric. Use the fact that L1 and L2 satisfy this to show that L3 satisfies it as well.
 
  • #12
L1 and L2 are two generical lorents tranformation. I must demostrate that their product is also a lorentz transormation.
Can I demostrate :

g_\alpha_\beta x^\alpha x^\beta = g_\mu_\nu \Lambda^\mu{}_\alpha \Lambda^\nu{}_\beta x^\alpha x^\beta

with \Lambda =L3= L1 L2 ?
 
  • #13
Yes you can.
 

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