Proving Lyapunov Stability for \(\dot{x} = Ax + B(t)x\)

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SUMMARY

The discussion centers on proving the Lyapunov stability of the system defined by the equation \(\dot{x} = Ax + B(t)x\), where \(A = \begin{bmatrix} 0 & 1 \\ -1 & 0 \end{bmatrix}\) and \(B(t) = \begin{bmatrix} 0 & 0 \\ 0 & \frac{2}{t} \end{bmatrix}\). The user is attempting to demonstrate that the trivial solution \((y, \dot{y}) = (0, 0)\) is unstable but is struggling due to the lack of eigenvalues of \(A\) with positive real parts. The discussion highlights the need for alternative theorems or methods to establish the instability of the trivial solution.

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motherh
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A question I am doing hints that the solution (y,\dot{y}) = (0,0) of \ddot{y} - \frac{2}{t}\dot{y} + y = 0 is unstable. I believe (although I am not 100% sure) that is true however I am struggling to prove it.

I can rewrite the equation as a system of equations in matrix form to get

\dot{x} = Ax + B(t)x,

where A = [{0,1},{-1,0}], B(t) = [{0,0},{0,\frac{2}{t}}].

This the form of all the theorems I appear to have. But all my theorems require me to find an eigenvalue of A with positive real part - which I can't here.

So basically have I made a mistake already or is there another theorem anybody knows of that can tell me the trivial solution is unstable?
 
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