Proving P1>Po: A Mathematical Analysis

[klezzie13]

Homework Statement

Prove that P1>Po

Homework Equations

dp=-rho(g)dy
integral(Po,P1)dp=-integral(Y2,Y1) rho(g)dy

The Attempt at a Solution

dp=-rho(g)dy
intgrl(Po,P1) dp=-integral(Y2,Y1) rho(g)dy
Po-P1=-(rho(g))(Y2-Y1)
Po-P1=(rho(g))(Y1-Y2)
Y2-Y1-->Y1-Y2<0 defined as -del(y)
Po-P1=-(rho)(g)(del(y))
P1-Po=+(rho)(g)(del(y))

not sure where to proceed or if this proves that P1>Po. Please help.

Oh and the attached file has a diagram on it.

 

[member 553083]

Since rho(g) is a positive constant, the equation P1-Po=+(rho)(g)(del(y)) implies that P1 is bigger than Po. Thus, P1>Po.