Proving Perfect Squares: A Study in Number Theory

  • Thread starter Thread starter dancergirlie
  • Start date Start date
  • Tags Tags
    Proof Squares
Click For Summary
To prove that a and b are perfect squares given that C^2 = ab and gcd(a, b) = 1, one can utilize the properties of prime factorization. Since a and b are relatively prime, their prime factors must be distinct, which implies that each prime factor must appear with an even exponent for both a and b to be perfect squares. The discussion highlights the realization that examining the prime factorizations simplifies the proof process. Initially, there was confusion about how to approach the proof, but the concept became clearer upon considering the prime factorization. Ultimately, the proof hinges on the relationship between the prime factors and their exponents.
dancergirlie
Messages
194
Reaction score
0

Homework Statement



If C^2 = ab and the greatest common divisor of a and b is equal to 1, prove that a and b are perfect squares

Homework Equations



I know that if (a,b)=1, then there exists integers u and v where 1=au+bv (even though i don't think this is necessary in this proof)

also, I know that the square root of a perfect square is a rational number, if it is not a perfect square, then it is irrational

Lastly, I know that since (a,b)=1 that means a and b are relatively prime


The Attempt at a Solution



I have absolutely no idea how to do this proof. I know i need to show that the square root of a and the square root of b are rational, but I don't know how to do that.

Maybe I could do it by trying to show it is irrational and finding a contradiction? Any help would be great!
 
Physics news on Phys.org
It's pretty easy conceptually if you think about the prime factorizations of a and b. Try that.
 
Yeah, I figured it out like 10 minutes after i posted, it is really easy now that I thought of the prime factorizations of a and b. Thanks for the help though!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
12
Views
2K
Replies
7
Views
3K