Proving Projectile Range&Height: Angle of Elevation 30deg vs 60deg

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SUMMARY

The discussion centers on proving that a projectile launched at an angle of elevation of 60 degrees reaches three times the height compared to one launched at 30 degrees, while maintaining the same horizontal distance. The equations used include the average velocity equation, s=(Vo + Vf)/2 * t, and the horizontal distance equation, x=Vo*cos(theta)*t. Participants noted that while the height equations were correctly simplified to y=0.25tan(30)x and y=0.25tan(60)x, the relationship between the ranges for both angles was not adequately demonstrated.

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Homework Statement


Prove that a gun will shoot three times as high wehn its angle of elevation is 60deg as when it is 30deg but will carry the same horizontal distance.



Homework Equations


s=(Vo +Vf)/2 * t
x=Vo*costheta *t

The Attempt at a Solution



AFter simplifying the equation i get:

y=0.25tan30x
y=0.25tan60x

is this correct?
 
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The equations are right but you haven't shown that the range of the two angles are the same... or the height at 60 is 3 times the height at 30.

you've related the range to the height for each situation... but you haven't related range to range.. and height to height.
 

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