Proving Root Space Invariancy of Linear Transformation

  • Context: MHB 
  • Thread starter Thread starter Sudharaka
  • Start date Start date
  • Tags Tags
    Root Space
Click For Summary
SUMMARY

The discussion focuses on proving that the root space \(V(\lambda)\) of a linear transformation \(f: V \rightarrow V\) is invariant under another transformation \(g: V \rightarrow V\) that commutes with \(f\). Participants clarify that a root space is equivalent to an eigenspace, which consists of all eigenvectors corresponding to a specific eigenvalue \(\lambda\), including the zero vector. The ambiguity surrounding the definition of root space among different authors is acknowledged, particularly referencing the book "Matrix And Linear Algebra 2Nd Ed." by Datta, which provides a standard definition.

PREREQUISITES
  • Understanding of linear transformations and their properties
  • Familiarity with eigenvalues and eigenspaces
  • Knowledge of commutative properties of linear operators
  • Basic concepts from linear algebra, particularly related to vector spaces
NEXT STEPS
  • Study the definitions and properties of eigenspaces in linear algebra
  • Learn about the implications of commutativity in linear transformations
  • Explore the concept of root spaces in various mathematical texts
  • Review examples of linear transformations and their invariant subspaces
USEFUL FOR

Students and professionals in mathematics, particularly those studying linear algebra, as well as educators seeking clarity on the concepts of root spaces and eigenspaces in the context of linear transformations.

Sudharaka
Gold Member
MHB
Messages
1,558
Reaction score
1
Hi everyone, :)

Here's a question that I don't quite understand.

Given \(f:\, V\rightarrow V\) and a root space \(V(\lambda)\) for \(f\), prove that \(V(\lambda)\) is invariant for \(g:,V\rightarrow V\) such that \(g\) commutes with f.

What I don't understand here is what is meant by root space in the context of a linear transformation. Can somebody please explain this to me or direct me to a link where it's explained?
 
Physics news on Phys.org
It looks as though a root space is what I would call an eigenspace, in other words the subspace of all eigenvectors corresponding to a given eigenvalue $\lambda$. (Strictly speaking, an eigenvector has to be nonzero, so the eigenspace is the set of all eigenvectors corresponding to $\lambda$, together with the zero vector.)
 
Opalg said:
It looks as though a root space is what I would call an eigenspace, in other words the subspace of all eigenvectors corresponding to a given eigenvalue $\lambda$. (Strictly speaking, an eigenvector has to be nonzero, so the eigenspace is the set of all eigenvectors corresponding to $\lambda$, together with the zero vector.)

Thanks very much for your valuable reply. :) There was some doubt on my mind as to what this root space is all about. It seems to me that there is some ambiguity about this depending on different authors. For example I was reading the following and it has a slightly different definition about the root space.

Matrix And Linear Algebra 2Nd Ed. - Datta - Google Books

However I don't know what my prof. had in his mind when writing down this question. So to make matters simple I shall take the eigenspace as the rootspace. Thanks again, and have a nice day. :)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K