Proving something is a vector space

In summary, the conversation discusses the set V = R^2 with vector addition and scalar multiplication operations. The individual attempts to show that V is a vector space, but questions the commutativity of the operations due to a potentially incorrect definition of vector addition. It is suggested to check with the professor for clarification.
  • #1
PsychonautQQ
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Homework Statement


Consider the set V = R^2 (two dimensions of real numbers) with the following operations of vector addition and scalar multiplication:

(x,y) + (z,w) = (x+y-1, y+z)
a(x,y) = (ax-a+1,ay)

Show that V is a vector space

Homework Equations


None

The Attempt at a Solution


So the first axiom of a vector space is showing that the scalar addition is commutative. However, to me it seems like given the wonky definition of vector addition it is not commutative.

(x,y) + (z,w) = (x+y-1, y+z)
(z,w) + (x,y) = (z+w-1, w+x)

These are only equal to each other if x=z and y=w. Do ya'll think this is a typo?
 
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  • #2
Yeah, I think it's a typo. You should check with your professor.
 

What is a vector space?

A vector space is a mathematical structure that consists of a set of objects (called vectors) and two operations (vector addition and scalar multiplication) that satisfy certain properties.

What are the properties that must be satisfied for something to be considered a vector space?

The properties that must be satisfied for something to be considered a vector space are closure under vector addition and scalar multiplication, associativity of vector addition, commutativity of vector addition, existence of an additive identity element, existence of additive inverses, distributivity of scalar multiplication over vector addition, and associativity of scalar multiplication.

How do you prove that something is a vector space?

To prove that something is a vector space, you must show that it satisfies all of the properties mentioned above. This can be done by checking each property individually and demonstrating that it holds for the given set of objects and operations.

Can something be a vector space with only one vector?

Yes, it is possible for something to be a vector space with only one vector. This is known as a trivial vector space, and it consists of just the zero vector with the operations of vector addition and scalar multiplication defined in a way that satisfies all of the properties of a vector space.

What is the importance of proving something is a vector space?

Proving that something is a vector space is important because it allows us to use the tools and techniques of linear algebra to study and understand the properties and relationships of the objects in that vector space. It also allows us to apply the concepts of vector spaces to other areas of mathematics and other fields, such as physics and engineering.

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