Proving something is a vector space

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SUMMARY

The discussion centers on proving that the set V = R^2, defined with specific operations of vector addition and scalar multiplication, constitutes a vector space. The operations are defined as (x,y) + (z,w) = (x+y-1, y+z) and a(x,y) = (ax-a+1, ay). A key point raised is the non-commutativity of the vector addition operation, leading to the conclusion that the definition may contain a typo, as the equality holds only under specific conditions.

PREREQUISITES
  • Understanding of vector space axioms
  • Familiarity with operations in R^2
  • Knowledge of scalar multiplication
  • Basic algebraic manipulation skills
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  • Research the axioms of vector spaces in linear algebra
  • Explore examples of vector addition and scalar multiplication in R^n
  • Learn about common errors in defining vector operations
  • Consult resources on communicating mathematical definitions clearly
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Students studying linear algebra, mathematics educators, and anyone interested in understanding the properties of vector spaces and their operations.

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Homework Statement


Consider the set V = R^2 (two dimensions of real numbers) with the following operations of vector addition and scalar multiplication:

(x,y) + (z,w) = (x+y-1, y+z)
a(x,y) = (ax-a+1,ay)

Show that V is a vector space

Homework Equations


None

The Attempt at a Solution


So the first axiom of a vector space is showing that the scalar addition is commutative. However, to me it seems like given the wonky definition of vector addition it is not commutative.

(x,y) + (z,w) = (x+y-1, y+z)
(z,w) + (x,y) = (z+w-1, w+x)

These are only equal to each other if x=z and y=w. Do ya'll think this is a typo?
 
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Yeah, I think it's a typo. You should check with your professor.
 

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