Proving Statements for Field Math: F/b = (ab^-1) and Other Equations

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Homework Help Overview

The discussion revolves around proving statements related to field mathematics, specifically focusing on the notation of division in a field context, where \( a/b \) is defined as \( ab^{-1} \). The original poster presents several statements that need to be proven for elements within a field, highlighting potential confusion regarding notation and the meaning of certain symbols.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants express uncertainty about the meaning of the dash in the notation, with some suggesting it indicates alternative values. Others question the interpretation of \( ab^{-1} \) and whether it represents multiplication or an inverse operation.

Discussion Status

There is an active exploration of the meanings behind the notation and the implications for the statements to be proven. Some participants are attempting to manipulate the equations to clarify their understanding, while others are sharing their interpretations and reasoning. No consensus has been reached, but various lines of reasoning are being explored.

Contextual Notes

Participants are grappling with the definitions and implications of the notation used in the problem statement, particularly regarding the use of dashes and the operations involved in field mathematics. There is also a focus on ensuring that the conditions for the statements, such as \( b \neq 0 \) and \( a' \neq 0 \), are acknowledged.

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Homework Statement


Let F be a field. For any a,b \in F, b\neq0, we write a/b for ab^-1. Prove the following statements for any a, a' \inF and b, b' \in F\{0}:

i.) a/b = a'/b' if and only if ab' =a'b
ii.) a/b +a'/b' = (ab'+a'b)/bb'
iii.) (a/b)(a'/b') = aa'/bb'
iv.) (a/b)/a'/b') = ab'/a'b (if in addition a'\neq0)


Homework Equations





The Attempt at a Solution



I'm struggling to understand how i am to prove these statements. What am i to take the dashes to mean, because they are often used to show inverses? So for the first one:

a/b=ab^-1 which = a^-1b = a'/b'?
 
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My guess is a dash means "alternative value." For example, a = 1, and a' = 2.
 
EnumaElish said:
My guess is a dash means "alternative value." For example, a = 1, and a' = 2.

I also thought that, i will go with that and see what i come up with, thanks
 
EnumaElish said:
My guess is a dash means "alternative value." For example, a = 1, and a' = 2.

Does ab^-1 mean a.b^-1 or (a.b)^-1? I think it might be the former.

If it is, i get:

i) a.b^-1 = a'.b'^-1 when written out fully. So if ab' = a'b, then rearranged gives a= a'b/b' and a' = ab'/b. So inserting them into a.b^-1 = a'.b'^-1 we get:

a'b.b^-1/b' = ab.b^-1/b

and then we get indentity elements leaving a'/b' = a/b

Is this right?
 

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