Proving that the limiting function is in Lp

  • Thread starter Thread starter bbkrsen585
  • Start date Start date
  • Tags Tags
    Function
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 1K views
bbkrsen585
Messages
10
Reaction score
0

Homework Statement



Hi guys. I have one question regarding convergence in Lp. Suppose gn converges to g mu-almost everywhere on [0,1]. Suppose further that [tex]\left\|[/tex]gn[tex]\left\|[/tex]p[tex]\rightarrow[/tex]M < [tex]\infty[/tex]. How do I show that the pointwise limit g is in Lp?

Thanks.

Homework Equations



So far, I know this is not true if we only know that gn goes to g mu-almost everywhere. I just don't see how the additional condition that the Lp-norms converge to some finite number implies that the limiting function g is also in Lp.
 
Physics news on Phys.org
But, how do we know that |gn|^p converges to |g|^p a.e.?

If gn goes to g almost everywhere does that imply that |gn|^p converges to |g|^p a.e.? That's not so clear to me. Thanks.