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Precalculus Mathematics Homework Help
Proving that there is no rational number whose square is two
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[QUOTE="mathwonk, post: 6071497, member: 13785"] if you know the lowest term form of a fraction is unique, you are almost done. i.e. if a/b is in lowest terms, i.e. a and b have no common prime factors, then so is a^2/b^2 in lowest terms, since the same prime factors occur here. But then a^2/b^2 = 2/1, and both sides are in lowest terms, hence tops and bottoms are equal, so a^2 = 2 and b^2 = 1. But no integer a can have a^2 = 2. done. [/QUOTE]
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Precalculus Mathematics Homework Help
Proving that there is no rational number whose square is two
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