Proving the Evenness of (\stackrel{2n}{n}) Using the Binomial Theorem

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ipitydatfu
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Homework Statement



prove that ([tex]\stackrel{2n}{n}[/tex]) is even when n [tex]\geq1[/tex]

Homework Equations



as a hint they gave me this identity:
[tex]\stackrel{n}{k}[/tex]= (n/k)([tex]\stackrel{n-1}{k-1}[/tex])

The Attempt at a Solution



by using that identity i got:

([tex]\stackrel{2n}{n}[/tex]) = (2n/n) ([tex]\stackrel{2n-1}{n-1}[/tex])
= (2) ([tex]\stackrel{2n-1}{n-1}[/tex])

i thought anything multiplied by 2 is an even number. but then again this is discrete math. how would i inductively show that this is true?
 
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That's pretty much it. The definition of "even number" is that it is of the form 2k for some integer k. Do you already know that [itex]\left(\begin{array}{c}n\\2i\end{array}\right)[/itex] is always an integer?