Proving the inclusion-exclusion principle

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SUMMARY

The discussion focuses on proving the general inclusion-exclusion formula, specifically the equation P(C1 U C2 U...U Ck) = p1 - p2 + p3 - ... + (-1)(k+1)pk. The formula is derived using mathematical induction, starting with the assumption that it holds for n sets and extending it to n+1 sets. The key steps involve calculating the probability of unions and intersections of sets, ultimately leading to the alternating pattern in the formula. The discussion highlights the importance of using inductive hypotheses to simplify complex probability expressions.

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  • Knowledge of union and intersection of sets
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Homework Statement



Prove the general inclusion-exclusion formula.

Homework Equations



Inclusion-exclusion Formula:

P(C1 U C2 U...U Ck) = p1 - p2 + p3 - ... + (-1)(k+1)pk

where pi equals the sum of the probabilities of all possible intersections involving i sets.

The Attempt at a Solution



Assume that the formula holds for n sets. Then for n+1 sets...

P(union k=1 to n+1 of Ck) = P((union k=1 to n of Ck) union Cn+1) = P(union k=1 to n of Ck) + P(Cn+1) - P((union k=1 to n of Ck) intersect Cn+1) = P(union k=1 to n of Ck) + P(Cn+1) - P(union k=1 to n of (Ck intersect Cn+1)) = sum k=1 to n of P(Ck) + P(Cn+1)...

From there I don't know how to show the alternating pattern.
 
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cookiesyum said:
P(union k=1 to n+1 of Ck) = P((union k=1 to n of Ck) union Cn+1) = P(union k=1 to n of Ck) + P(Cn+1) - P((union k=1 to n of Ck) intersect Cn+1) = P(union k=1 to n of Ck) + P(Cn+1) - P(union k=1 to n of (Ck intersect Cn+1)) = sum k=1 to n of P(Ck) + P(Cn+1)...

From there I don't know how to show the alternating pattern.

You can use your inductive hypothesis to write out

P(union k=1 to n of Ck)

and

P((union k=1 to n of Ck) intersect Cn+1)

Using the fact that Cn+1 intersected with the union from 1 to n of Ck is the same as the union from 1 to n of (Ck intersected with Cn+1)
 

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