Proving the Limit of (x^2)(sin y)^2)/(x^2+2y^2) at (0,0) without Squeeze Theorem

  • Thread starter Thread starter chaose
  • Start date Start date
  • Tags Tags
    Limit
Join the discussion
Registration is free. Start your own thread to ask a follow-up.
2 replies · 2K views
chaose
Messages
10
Reaction score
0
Is there anyway to show that the limit for ((x^2)(sin y)^2)/(x^2+2y^2) exists without using the squeeze theorem? I was thinking about the episilon-delta definition of the limit.sorry, I forgot the values.
limit (x,y) -> (0,0) of ((x^2)(sin y)^2)/(x^2+2y^2)
 
Last edited:
Physics news on Phys.org
chaose said:
Is there anyway to show that the limit for ((x^2)(sin y)^2)/(x^2+2y^2) exists without using the squeeze theorem? I was thinking about the episilon-delta definition of the limit.

You forgot to specify the 'variable -> value' part.
 
Convert to polar coordinates.