Proving the Limit of (x^2)(sin y)^2)/(x^2+2y^2) at (0,0) without Squeeze Theorem

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The limit of the function ((x^2)(sin y)^2)/(x^2+2y^2) as (x,y) approaches (0,0) can be established using the epsilon-delta definition of limits and polar coordinates. By converting to polar coordinates, where x = r*cos(θ) and y = r*sin(θ), the limit simplifies to a form that can be analyzed without the Squeeze Theorem. This approach confirms that the limit exists and is equal to 0 as r approaches 0.

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Is there anyway to show that the limit for ((x^2)(sin y)^2)/(x^2+2y^2) exists without using the squeeze theorem? I was thinking about the episilon-delta definition of the limit.sorry, I forgot the values.
limit (x,y) -> (0,0) of ((x^2)(sin y)^2)/(x^2+2y^2)
 
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chaose said:
Is there anyway to show that the limit for ((x^2)(sin y)^2)/(x^2+2y^2) exists without using the squeeze theorem? I was thinking about the episilon-delta definition of the limit.

You forgot to specify the 'variable -> value' part.
 
Convert to polar coordinates.
 

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