Proving the Non-Negativity of a Decreasing Sequence with Limit 0

In summary, the conversation is about analyzing and proving a sequence that is decreasing and has a limit of 0. The objective is to prove that the sequence is greater than or equal to 0 for every n in the natural numbers. This can be done by showing that if a particular choice of epsilon is made and a_{\bar{n}}<0, then the limit definition will not be satisfied. It is important to take into account that the sequence is decreasing.
  • #1
Armbru35
7
0
Analysis Proof Help!

If anyone could give me a hint on how to start this I would appreciate it! I am struggling with proofs! Thanks!

Given a sequence (asub(n))
s.t.
(i) the sequence is decreasing
(ii) the limit of the sequence is 0.
Prove rigorously that an is greater than or equal to 0 for every n contained in the natural numbers
 
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  • #2


[itex]a_n\rightarrow 0[/itex] if [itex]\forall \epsilon >0\exists \bar{n}\backepsilon' \forall n>\bar{n}, |a_n|<\epsilon[/itex].
Try to prove that, if [itex]a_{\bar{n}}<0[/itex], with a particular choice of epsilon the limit definition is not verified.
Remember to consider the fact that the sequence is decreasing
 

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