Proving the Subgroup Property of Even Permutations in Permutation Groups

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The discussion centers on proving that the set of all even permutations in a group G forms a subgroup. Participants explore the necessary conditions for a subset to be a subgroup, including closure under multiplication, the presence of the identity element, and the existence of inverses. It is suggested that if both a and b are even permutations, their product ab is also an even permutation, supporting the closure property. Additionally, the identity permutation is confirmed to be even, and it is noted that the inverse of an even permutation is also even. Overall, the conversation emphasizes the simplicity of the proof while addressing key subgroup properties in the context of permutations.
PhysicsUnderg
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Homework Statement


Show that if G is any group of permutations, then the set of all even permutations in G forms a subgroup of G.

I am not sure where to start - I know there is a proposition that states this to be true, but I know that is not enough to prove this statement.
 
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Hi PhysicsUnderg! :smile:

Hint: if H is a subgroup of G, then for any a and b in H, the product ab must also be in H. :wink:
 
Is it really that simple? lol This is what I was thinking, but I wasn't sure how to connect the idea to permutations. Can I just say "a is an even permutation" and "b is an even permutation" thus "a*b is also an even permutation"? Because, if this is true and if I assume that a and b are elements of H, then ab is an element of H and is an even permutation, so G has a subgroup of even permutations. Also, for H to be a subgroup, the identity element must be contained in H, as well as an inverse. How do you connect this to permutations?
 
Hi PhysicsUnderg! :smile:
PhysicsUnderg said:
Is it really that simple?

Yes! :biggrin:

Sometimes, maths really is that simple! :wink:
… Also, for H to be a subgroup, the identity element must be contained in H, as well as an inverse. How do you connect this to permutations?

You ask "Is the identity an even permutation? What is the inverse of an even permutation?" :smile:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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