Proving the Subgroup Property of Even Permutations in Permutation Groups

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Homework Help Overview

The discussion revolves around proving that the set of all even permutations in a group of permutations forms a subgroup of that group. The subject area is group theory, specifically focusing on permutation groups and properties of even permutations.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the definition of a subgroup and consider the implications of even permutations. There is discussion about whether the product of two even permutations is also an even permutation and the necessity of including the identity element and inverses in the subgroup.

Discussion Status

Some participants have provided hints and guidance regarding the subgroup criteria, while others express uncertainty about connecting these ideas specifically to permutations. Multiple interpretations of the requirements for a subgroup are being explored.

Contextual Notes

Participants are questioning how to demonstrate that the identity element and inverses of even permutations fit within the framework of the subgroup definition. There is also a mention of a proposition that supports the claim but lacks a detailed proof.

PhysicsUnderg
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Homework Statement


Show that if G is any group of permutations, then the set of all even permutations in G forms a subgroup of G.

I am not sure where to start - I know there is a proposition that states this to be true, but I know that is not enough to prove this statement.
 
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Hi PhysicsUnderg! :smile:

Hint: if H is a subgroup of G, then for any a and b in H, the product ab must also be in H. :wink:
 
Is it really that simple? lol This is what I was thinking, but I wasn't sure how to connect the idea to permutations. Can I just say "a is an even permutation" and "b is an even permutation" thus "a*b is also an even permutation"? Because, if this is true and if I assume that a and b are elements of H, then ab is an element of H and is an even permutation, so G has a subgroup of even permutations. Also, for H to be a subgroup, the identity element must be contained in H, as well as an inverse. How do you connect this to permutations?
 
Hi PhysicsUnderg! :smile:
PhysicsUnderg said:
Is it really that simple?

Yes! :biggrin:

Sometimes, maths really is that simple! :wink:
… Also, for H to be a subgroup, the identity element must be contained in H, as well as an inverse. How do you connect this to permutations?

You ask "Is the identity an even permutation? What is the inverse of an even permutation?" :smile:
 

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