Proving the Sum of Vector Areas in a Tetrahedron is Zero

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Homework Help Overview

The discussion revolves around proving that the sum of four vectors, each representing the area of a face of a tetrahedron and oriented outward, equals zero. The problem also extends to formulating a similar statement for a planar triangle.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss expressing the vectors in terms of the edges of the tetrahedron and explore the analogy to a planar triangle. Questions arise regarding the definition of a "planar triangle" and the relationship between area and length in this context.

Discussion Status

Some participants have attempted to clarify the problem and suggest methods for visualizing the vectors in both the tetrahedron and triangle cases. There is a request for further explanation from those who have solved the problem, indicating an ongoing exploration of the concepts involved.

Contextual Notes

Participants note the need for clarity on the term "planar triangle" and discuss assumptions about the geometric properties of the shapes involved.

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Homework Statement


Four vectors are erected perpendicular to the four faces of a general tetrahedron. Each vector is pointing outwards and has a length equal to the area of the face. Show that the sum of these four vectors is zero.

Homework Equations



The Attempt at a Solution


Let A, B and C be vectors representing the three edges starting from a fixed vertex. Then, express each of the four vectors in terms of A, B and C.
 
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I figured out how to do the problem.

But there's another part to the problem: Formulate and prove the analogous statement for a plane triangle.

What is meant by a "planar triangle"?
 


i think it probably just means any normal triangle (normal in the sense that it is contained within in a plane in R^3, so planar)

can you show it for such? where I'm guessing the analogy is area to length
 


Put your triangle in the xy plane; label the vertices A,B,C clockwise. Make vectors of the sides going from A to B, B to C, C to A (i.e, \vec a = B - A etc.). Those side vectors add to the zero vector. Now rotate the triangle 90 degrees counterclockwise and they become perpendicular to the original sides pointing outward and the right length. Presto!
 


I am trying to solve this same problem. Would the person who asked the question and said he/she figured it out please tell me how its done? Unfortunately, it is just not clicking with me. Thank you.
 


Could you explain how you solved this?
 

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