Proving triangles with vector methods

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The discussion focuses on proving that the length of segment DE is half the length of segment BC using vector methods. The initial equations establish that AD and AE are half the lengths of AB and AC, respectively. A series of vector manipulations leads to the conclusion that DE equals 1/2 BC. However, corrections are suggested regarding the signs in the equations and the presentation format for clarity. The final proof confirms that DE = 1/2BC, validating the relationship between the segments.
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Homework Statement



In the following diagram D and E are the midpoints of AB and AC. Use vector methods to prove that DE = 1/2BC

Homework Equations



DE = 1/2 BC

The Attempt at a Solution



AD = 1/2AB
AE = 1/2AC

AD + DE = AE
DE = -AE + AD
DE = -1/2AC + 1/2AD
IF BC = -AC + AB
AND DE = -1/2AC + 1/2AB
THEN 1/2BC = DE
Diagram -
detriangle.jpg
 
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hi crayzwalz! :smile:

yes, that's correct, except …

i] your + and - are the wrong way round in

DE = -AE + AD
and
IF BC = -AC + AB

ii] you should write it all out in one sequence, with the first line

DE =

and the last line

= 1/2BC :wink:
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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