Proving trig identities with dot and cross products

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Homework Help Overview

The discussion revolves around proving trigonometric identities using dot and cross products of two vectors, a and b, which lie in the xy-plane and make angles α and β with the x-axis. The identities in question include cos(α-β) and sin(α-β), as well as a related expression for cos(α+β).

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss evaluating the dot product in two ways to establish the trigonometric identities. There is an exploration of the components of vectors a and b in terms of their magnitudes and angles. Some participants express uncertainty about relating their findings to the identities.

Discussion Status

Participants are actively engaging with the problem, sharing their attempts to express vector components and relate them to the identities. Some guidance has been offered regarding the correct expressions for the components of the vectors, and there is a recognition of the need to apply these components to complete the proofs.

Contextual Notes

There is a focus on ensuring the correct interpretation of vector components and their relationships to the angles involved. Participants are also considering the implications of the vectors being confined to the xy-plane.

cytochrome
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Homework Statement



The two vectors a and b lie in the xy plane and make angles α and β with the x axis.

a)By evaluating ab in two ways (Namely ab = abcos(θ) and ab = a1b1+a2b2) prove the well-known trig identity
cos(α-β)=cos(α)cos(β)+sin(α)sin(β)

b)By similarly evaluating a X b prove that
sin(α-β) = sin(α)cos(β) - cos(α)sin(β)

c)Now let vector a make an angle -α with the x axis and find a similar expression for
cos(α+β)


Homework Equations



ab = abcos(θ)

ab = a1b1+a2b2



The Attempt at a Solution



I drew the vectors a and b with their appropriate angles to the x-axis... The angle between the vectors is (α-β) so I have ab = abcos(α-β) but I have no idea how to relate this to the trig identities!
 
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cytochrome said:

Homework Statement



The two vectors a and b lie in the xy plane and make angles α and β with the x axis.

a)By evaluating ab in two ways (Namely ab = abcos(θ) and ab = a1b1+a2b2) prove the well-known trig identity
cos(α-β)=cos(α)cos(β)+sin(α)sin(β)

b)By similarly evaluating a X b prove that
sin(α-β) = sin(α)cos(β) - cos(α)sin(β)

c)Now let vector a make an angle -α with the x axis and find a similar expression for
cos(α+β)

Homework Equations



ab = abcos(θ)

ab = a1b1+a2b2

The Attempt at a Solution



I drew the vectors a and b with their appropriate angles to the x-axis... The angle between the vectors is (α-β) so I have ab = abcos(α-β) but I have no idea how to relate this to the trig identities!
What are the components of vector, a, in terms of a (the magnitude of the vector) and the angle α?

What are the components of vector, b, in terms of b (the magnitude of the vector) and the angle β?
 
SammyS said:
What are the components of vector, a, in terms of a (the magnitude of the vector) and the angle α?

What are the components of vector, b, in terms of b (the magnitude of the vector) and the angle β?

The components of a are ax*cos(α) and ay*sin(α)

The components of b are bx*cos(β) and by*sin(β)

Thanks for reminding me about that I'll see where I can get from here
 
cytochrome said:
The components of a are ax*cos(α) and ay*sin(α)

The components of b are bx*cos(β) and by*sin(β)

Thanks for reminding me about that I'll see where I can get from here

Not quite right.

The components of a are ax = a*cos(α) and ay = a*sin(α)

etc.

B.T.W. ax = a1, etc. in your Relevant equations for the dot & cross products.
 
What are a1, a2, b1, and b2 in terms of a, b, α, and β?
 
vela said:
What are a1, a2, b1, and b2 in terms of a, b, α, and β?

a1 = acos(α)
a2 = asin(α)

b1 = bcos(β)
b2 = bsin(β)

a dot b = acos(α)bcos(β) + asin(α)bsin(β)

which pretty much completes the proof for a)
 
cytochrome said:
a1 = acos(α)
a2 = asin(α)

b1 = bcos(β)
b2 = bsin(β)

a dot b = acos(α)bcos(β) + asin(α)bsin(β)

which pretty much completes the proof for a)
Do something similar for (b).

( a × b )3 = a1*b2 - a2*b1 . If both vectors are in the xy-plane, then the other components are zero.
 

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