Proving Trig Identity: (Sin2x-tanx)/cos2x=tanx

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SUMMARY

The trigonometric identity to prove is (Sin2x - tanx) / cos2x = tanx. Utilizing the identities sin 2x = 2 sin x cos x and tan x = sin x / cos x, the right-hand side can be expressed as (2 sin x cos x - sin x / cos x) / cos 2x. The next step involves combining the terms in the numerator into a single fraction with a common denominator of cos x and then factorizing.

PREREQUISITES
  • Understanding of trigonometric identities, specifically sin 2x and tan x.
  • Ability to manipulate algebraic fractions.
  • Familiarity with the cosine double angle formula, cos 2x.
  • Basic knowledge of factorization techniques in algebra.
NEXT STEPS
  • Study the derivation and applications of the sine double angle identity, sin 2x = 2 sin x cos x.
  • Learn how to simplify and manipulate algebraic fractions in trigonometric contexts.
  • Explore the cosine double angle formula, cos 2x, and its implications in trigonometric proofs.
  • Practice proving various trigonometric identities to enhance problem-solving skills.
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Students studying trigonometry, mathematics educators, and anyone interested in mastering trigonometric identities and proofs.

paix1988
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May someone kindly assist me to prove this trig identity

(Sin2x-tanx) / cos2x = tanx

Thank you for your assistance
 
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paix1988 said:
May someone kindly assist me to prove this trig identity

(Sin2x-tanx) / cos2x = tanx

Thank you for your assistance

Making use of the identities $\sin 2x = 2 \sin x \cos x$ and $\tan x = \sin x / \cos x$ we can write the RHS as:
$$\frac{2 \sin x \cos x -\frac{\sin x}{\cos x}}{\cos 2x}.$$
To proceed, write the numerator as one fraction (thus with denominator $\cos x$) and factorize!
 

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