Proving Uniform Convergence of f_n = x/sqrt(1+nx^2) on R

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SUMMARY

The function \( f_n(x) = \frac{x}{\sqrt{1+nx^2}} \) converges uniformly to 0 on all real numbers. To establish uniform convergence, one must demonstrate that for every \( \epsilon > 0 \), there exists an \( N \) such that for all \( n \geq N \), the inequality \( |f_n(x) - 0| < \epsilon \) holds for all \( x \in \mathbb{R} \). The correct approach involves ensuring that the expression \( \frac{x}{\sqrt{1+nx^2}} < \epsilon \) can be satisfied without dependence on \( x \). The algebraic manipulation must accurately account for the square root in the denominator.

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Homework Statement


Prove that [tex]f_{n} = \frac{x}{\sqrt{1+nx^2}}[/tex] is uniformly convergent to 0 on all real numbers


Homework Equations


{f_n} is said to converge uniformly on E if there is a function f:E->R such that for every epsilon >0, there is an N where n>=N implies that | f_n(x) - f(x) | < epsilon, for all x in E.


The Attempt at a Solution


Let f(x) = lim n-> infty f_n(x), and let epsilon > 0. Then it is obvious, that if n>1, that as n -> infty, the limit goes to 0, and thus we would need to show that [tex]\frac{x}{\sqrt{1+nx^2}} < epsilon[/tex]| , which happens as long as n > [tex]\frac{\frac{x}{epslion}-1}{x^2}[/tex]. So, I feel like I got it, except for the 'obvious' statement that f(x) = 0. Am I doing this right? Thanks ahead of time.
 
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i) you want to show lim n->infinity f_n(x)=0 for all x. That tells you the pointwise limit is 0. ii) your algebra is wrong, what happened to the sqrt? ii) There shouldn't be an x in your expression for choosing n. That's what 'uniform' convergence is all about.
 

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