Proving Uniqueness in Continuous Functions with Positive Values

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SUMMARY

The discussion focuses on proving the uniqueness of τ in the context of a continuous function k(t) with positive values. It establishes that for any t, there exists a unique τ defined by the integral τ = ∫(k(η)dη, 0, t). The reasoning hinges on the property that the antiderivative of k(t) is strictly increasing due to the positivity of k(t), ensuring that different values of t yield different values of τ. The participants emphasize the necessity of demonstrating that if two τ values exist for the same t, they must be identical, reinforcing the one-to-one correspondence between t and τ.

PREREQUISITES
  • Understanding of continuous functions and their properties
  • Knowledge of definite integrals and antiderivatives
  • Familiarity with the concept of one-to-one functions
  • Basic calculus, particularly the Fundamental Theorem of Calculus
NEXT STEPS
  • Study the Fundamental Theorem of Calculus to understand the relationship between differentiation and integration
  • Explore the properties of continuous functions and their implications on integrals
  • Learn about the concept of injective functions and how to prove uniqueness
  • Investigate examples of continuous functions to practice proving uniqueness in similar contexts
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Students studying calculus, mathematicians interested in function properties, and educators looking for examples of proving uniqueness in continuous functions.

proximaankit
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Homework Statement



Suppose that k(t) is a continuous function with positive values. Show that for any t (or at least for any t not too large), there is a unique τ so that τ =∫ (k(η)dη,0,t); conversely
any such τ corresponds to a unique t. Provide a brief explanation on why there is such a 1-1 correspondence.


Homework Equations


NA


The Attempt at a Solution


Stuck on it but here are some of my thoughts and reasoning:

I first view τ as function dependent upon t. since k(t) is positive and continuous, that will mean that the antiderivative of k(t) will only give us increasing values for increasing t. The new k(η) function is essentially same as k(t) except with η as the independent var. Hence since the k(t) is positive then k(η) is also positive. Then the integral of k(η) must be increasing for each increasing t. Hence for t2 and t1 the integral of k(η) from 0 to t2 is greater than the integral of k(η) from 0 to t1. This makes sure the for every different t substitute into the integral have a different output. And as we said τ is


The problem is how do I show the unique τ for each t part.

Thank you very much in advance for any help :)
 
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proximaankit said:

Homework Statement



Suppose that k(t) is a continuous function with positive values. Show that for any t (or at least for any t not too large), there is a unique τ so that τ =∫ (k(η)dη,0,t); conversely
any such τ corresponds to a unique t. Provide a brief explanation on why there is such a 1-1 correspondence.


Homework Equations


NA


The Attempt at a Solution


Stuck on it but here are some of my thoughts and reasoning:

I first view τ as function dependent upon t. since k(t) is positive and continuous, that will mean that the antiderivative of k(t) will only give us increasing values for increasing t. The new k(η) function is essentially same as k(t) except with η as the independent var. Hence since the k(t) is positive then k(η) is also positive. Then the integral of k(η) must be increasing for each increasing t. Hence for t2 and t1 the integral of k(η) from 0 to t2 is greater than the integral of k(η) from 0 to t1. This makes sure the for every different t substitute into the integral have a different output. And as we said τ is


The problem is how do I show the unique τ for each t part.

Thank you very much in advance for any help :)

Is this supposed to be an if and only if or are you to prove that for any ##t## there is a unique ##τ##?

If it's the latter, you should start by assuming there are two unique ##τ## and then show that they both must be the same.
 

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