- #31
member 731016
Thank you for your replies @haruspex and @kuruman !
So since gravity is acting in the ##\hat k## direction means that the torque due to gravity on the putty is along the plane of rotation.
This means when the putty collides with the puck then the angular momentum of the puck in the ##\hat k## direction cannot be changed since the putty angular momentum dose not have component in the ##\hat k## direction since when it is falling is has angular momentum along the plane (in either the ##\hat x## or ##\hat y## direction or both) given by the right hand rule.
I see now that the solution should have specified that angular momentum is conserved in the ##\hat k## direction about the AoR. Now I see that they should have applied conservation of angular momentum in the ##\hat k## direction which is why the putty's angular velocity is zero.
Many thanks!
So since gravity is acting in the ##\hat k## direction means that the torque due to gravity on the putty is along the plane of rotation.
This means when the putty collides with the puck then the angular momentum of the puck in the ##\hat k## direction cannot be changed since the putty angular momentum dose not have component in the ##\hat k## direction since when it is falling is has angular momentum along the plane (in either the ##\hat x## or ##\hat y## direction or both) given by the right hand rule.
I see now that the solution should have specified that angular momentum is conserved in the ##\hat k## direction about the AoR. Now I see that they should have applied conservation of angular momentum in the ##\hat k## direction which is why the putty's angular velocity is zero.
Many thanks!