Pulsed DC into inductor turns to AC?

  • Thread starter Thread starter hobbs125
  • Start date Start date
  • Tags Tags
    Ac Dc Inductor
Click For Summary
SUMMARY

Pulsed DC applied to an inductor can produce AC-like waveforms due to the inductor's self-resonance frequency, resulting in a ringing effect at the edges of the pulse. When the frequency of the square wave matches the inductor's resonant frequency, the output resembles an AC waveform, as the square wave loses high-frequency components and approaches a sine wave. The discussion clarifies that DC refers to unidirectional current, while pulsed signals can exhibit both DC and AC characteristics depending on their frequency components.

PREREQUISITES
  • Understanding of inductors and their behavior in circuits
  • Knowledge of waveform characteristics, including AC and DC components
  • Familiarity with resonant frequency concepts in electrical engineering
  • Basic principles of pulse width modulation and square wave generation
NEXT STEPS
  • Research inductor self-resonance and its effects on waveform output
  • Learn about parallel tank circuits and their applications in signal processing
  • Study the relationship between pulse width modulation and frequency components
  • Explore the differences between AC and DC signals in electrical engineering
USEFUL FOR

Electrical engineers, circuit designers, and students studying waveform behavior in inductive circuits will benefit from this discussion.

hobbs125
Messages
108
Reaction score
0
What is it that causes pulsed dc into an inductor to turn into ac?

Are their specific frequencies at which this occurs (i.e. inductors self resonance frequency)?
 
Engineering news on Phys.org
What you can get is a ringing effect just after the rising and falling edges of the pulse.

Like this:

images?q=tbn:ANd9GcTZhBSWEC8pFOJwXcbLRDPjTIIc6JSt-8HJPm0pytpMUSjWB8s5.jpg


The ringing on the lower edge does go negative, so you could call it AC.

On large coils, and with large currents, these negative going pulses can have very high amplitude.

The frequency of the ringing would be the same as the resonant frequency of the inductor.
 
What if the square waves are at the inductors resonant frequency. Then the inductor would effectively be a parallel tank circuit. In this case wouldn't the inductors output be an ac waveform?
 
I thought DC mean stable, unchanged current. Pulse is a pulse even it go from a set low voltage to a set high voltage. A pulse train can be separated into different frequency components(AC) with a DC component super imposed onto each other. There is no pulsed DC.
 
Last edited:
hobbs125 said:
What if the square waves are at the inductors resonant frequency. Then the inductor would effectively be a parallel tank circuit. In this case wouldn't the inductors output be an ac waveform?

You say "pulsed dc" applied across an inductor. But this an incomplete question. Is it a low impedence voltage source, or a current source? Does the impedence change with applied voltage and removal of the voltage/current source?

You have another source of confusion: there is no difference between the applied voltage/current across an inductor and the output. They are the same.
 
yungman said:
I thought DC mean stable, unchanged current. Pulse is a pulse even it go from a set low voltage to a set high voltage. A pulse train can be separated into different frequency components(AC) with a DC component super imposed onto each other.

I say it is definitely not DC.

DC means Direct Current or unidirectional current, not constant current.

See Wikipedia:
Direct current (DC) is the unidirectional flow of electric charge.

You can have a DC pulse. That is what comes out of logic gates when they vary rapidly in output from 0 volts to 5 volts. It isn't AC because it has only one polarity.

What if the square waves are at the inductors resonant frequency. Then the inductor would effectively be a parallel tank circuit. In this case wouldn't the inductors output be an ac waveform?

There would certainly be a component at the resonant frequency.

The square wave would lose all its high frequency components and become more like a sinewave at the resonant frequency.

This would only work if the inductor was fed from a large resistor in series with the signal generator.
 
As Phrak says. The question is incomplete. This is just a general arm-waving discussion about non-specific situations. There are better things to do than argue about the etymology of electrical terms - some Engineers being what they are, they can be very sloppy in their terminology at times.
A waveform, in general, will have DC and AC components. Nothing more to be said, usefully, unless the waveform and the circuit producing it are specified.
 

Similar threads

Replies
13
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 48 ·
2
Replies
48
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
Replies
21
Views
2K
  • · Replies 25 ·
Replies
25
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
10
Views
3K