Pumping a Cylindrical Storage Tank (different variables)

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Homework Help Overview

The problem involves calculating the work required to pump olive oil from a horizontally oriented cylindrical storage tank. The tank has a diameter of 8 feet and a length of 20 feet, and the olive oil has a specific weight density. The task is to determine the work needed to raise the oil to a height of 6 feet above the tank.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants discuss the orientation of the tank and its implications for the problem setup. There are questions about whether the tank is lying on its curved surface or its side, and how this affects the calculations. Some participants attempt to clarify the meaning of "lying horizontally" and its relevance to the problem.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the tank's orientation and its impact on the problem. Some guidance has been offered regarding the setup, but there is no explicit consensus on the correct interpretation or approach.

Contextual Notes

Participants note potential confusion regarding the dimensions of the tank and how they relate to the calculations. There are also references to typical configurations of similar tanks, which may influence assumptions about the problem setup.

dudicuff
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Homework Statement


A cylindrical storage tank 8 feet in diameter and 20 feet long is lying horizontally on the ground. The tank is full of olive oil whose weight density is 57 lb/ft^3. How much work does it take to pump the olive oil to a level of 6 feet above the top of the tank?

Almost identical to one posted a while ago.


Homework Equations



V = 20 * 2x

[tex]\int[/tex] [from -4 to 4] 20 * 2 * 57 * (14 - y) * ([tex]\sqrt{}16 - y^2[/tex]) dy

The Attempt at a Solution



Cranked it out and got 255360 pi -97280 ft - lbs
or 704957 ft - lbs


I think this is right, but an affirmative by a few more people would be a great help.
 
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Does "lying horizontally" mean that the cylindrical tank is lying on its curved surface?
 
No, actually it means it is lying on the side that is 20ft. I think I got the answer, though. I needed to do my distance from (10 - y) because the origin is in the middle.
 
Ok this is confusing. Isn't the 20ft a measurement of the height of the tank? And if it is lying down on that side, wouldn't it be lying on the curved surface? Another (quite unlikely) possibility would be that it is somehow balanced on its curved edge.
 
Defennder said:
Does "lying horizontally" mean that the cylindrical tank is lying on its curved surface?

dudicuff said:
No, actually it means it is lying on the side that is 20ft. I think I got the answer, though. I needed to do my distance from (10 - y) because the origin is in the middle.
The "side that is 20 ft" is the curved side! You meant "yes".

Defennder said:
Ok this is confusing. Isn't the 20ft a measurement of the height of the tank? And if it is lying down on that side, wouldn't it be lying on the curved surface? Another (quite unlikely) possibility would be that it is somehow balanced on its curved edge.
Why is that "quite unlikely"? That's the way small fuel tanks are normally positioned.
 
Here's a picture to clarify:

_
l`````````l.l
6ft```````l.l`<- Spout for pump.
l`````````l.l
_
l````````` ___``_______________________________
l````````/...\ ----------------------------------\
l```````/....\----------------------------------\
l``````/....\---------------------------------\
8 ft```l......l---------------------------------l
l``````\...../---------------------------------/
l```````\.../---------------------------------/
l````````\...___.../_____________________________/
l
_```````````````l------------- 20 ft ---------------l

Lying horizontally on the side that is 20 ft.
 
A "layer" of water at a given height is a rectangle. The length of that rectangle is 20 ft. The width depends upon the height.
 
I didn't do the problem but by the setup it seems correct.
 

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