(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A factory worker pushes a 32.0 kg crate a distance of 5.0 m along a level floor at constant velocity by pushing horizontally on it. The coefficient of kinetic friction between the crate and floor is 0.25. The factory worker pushes downward at an angle of 40° below the horizontal.

What magnitude of force must the worker apply to move the crate at a constant velocity?

2. Relevant equations

Fn= mg+Fy

fk=.25Fn

Fy=Fsin(40)

3. The attempt at a solution

I spent a long time trying to figure this out, I know mg=313.6N and i need to add the force of the y component to that to find the normal force, but I don't know how to find Fy, or Fx. If there was no vertical push it would just be 78.4N in the x direction, which equals the force of friction. But with the vertical push it seems like the harder you push, the more friction increases, and thus you need to push harder. I saw other people have had the same question on this forum before, but with different numbers, but they don't help me because people only told them that the vertical push makes the normal force bigger, but I don't know how to calculate the vertical push.

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# Homework Help: Pushing at a downward angle with friction

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