- #1
almstlwftmlk
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1. You are pushing a box of mass 18kg with a force of 239 N at 34.7 degrees below the horizontal. The box is on an inclined plane at angle 15 degrees above the horizontal. What is the acceleration of the box up the ramp?
2. F=ma
Fpush-Fgx = ma
Fgx = (Fg)(sin(15))
Fpush = (Fg)(cos(34.7))
Fpush - Fgx = ma
145.174 N - 45.702 N = (18kg)(a)
a = 5.5262 m/s/s
2. F=ma
Fpush-Fgx = ma
The Attempt at a Solution
Fgx = (Fg)(sin(15))
Fpush = (Fg)(cos(34.7))
Fpush - Fgx = ma
145.174 N - 45.702 N = (18kg)(a)
a = 5.5262 m/s/s