A 90 kg box is pushed by a horizontal force F at constant speed up a ramp inclined at 28°, as shown. Determine the magnitude of the applied force.
- when the ramp is frictionless.
- when the coefficient of kinetic friction is 0.18
The Attempt at a Solution
a) mg=(90)((.8)= 882N=Fg
414N=Fgx= magnitude of applied force
b) FN=mg= 882N
** This is where I am unsure of my approach**
That seems like too much to me, but I'm not quite sure. Does it look like I have that equation correct ,or am I supposed to subtract the value I found for Fk from FgX, or something totally different. Any help would be very much appreciated