- #1
Kathy W
- 4
- 0
Homework Statement
A 90 kg box is pushed by a horizontal force F at constant speed up a ramp inclined at 28°, as shown. Determine the magnitude of the applied force.
- when the ramp is frictionless.
- when the coefficient of kinetic friction is 0.18
Homework Equations
F=mg
FN=mg
μ= Fk/FN
The Attempt at a Solution
a) mg=(90)((.8)= 882N=Fg
sin28=Fgx/882N
(0.469)(882)= Fgx
414N=Fgx= magnitude of applied force
b) FN=mg= 882N
μ=Fk/FN
0.18=Fk/882
(882)(0.18)= Fk
Fk= 158.76
** This is where I am unsure of my approach**
Fapplied= Fgx+Fk
=414N+158.76 N
= 572N
That seems like too much to me, but I'm not quite sure. Does it look like I have that equation correct ,or am I supposed to subtract the value I found for Fk from FgX, or something totally different. Any help would be very much appreciated