(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

There are two blocks touching each other, block A, and block B. Block A is being pushed by a force, which in turn moves block A and B at the same time. Block A has a mass of 4kg, block B has a mass of 1kg. (so the force is pushing the larger block, which is pushing the smaller block).

When the hand starts to push, the blocks are moving with a speed of 2.0 m/s. Suppose that the work done by the hand on block A during a given displacement is 10 J. Determine the final kinetic energy of each block

2. Relevant equations

Change in work (f * d) = change in kinetic energy ( 1/2m(vf)^2 - 1/2m(vi)^2)

3. The attempt at a solution

10J = Kf - 1/2(4kg)(2m/s)^2, Kf = 18J

10J = Kf - 1/2(1kg)(2m/s)^2, Kf = 12J

Now to me, this seems like a pretty straight forward problem. However, my fellow students are getting a different answer. Perhaps I am overlooking something? Any help is appreciated.

Thanks

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Pushing two blocks

**Physics Forums | Science Articles, Homework Help, Discussion**