QM, central potential, system collapse

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SUMMARY

The discussion centers on a quantum mechanics problem involving a homogeneous system of spin 1/2 particles under a central, spin-independent potential V. The expectation value of the Hamiltonian is expressed as E^{(0)} + E^{(1)} = 2 ∑_k^{k_F} (ℏ² k² / 2m) + 1/2 ∑_{k λ}^{k_F} ∑_{k' λ'}^{k_F} [ - ]. The key conclusion is that if the energy per particle, (E^{(0)} + E^{(1)}) / N, decreases with increasing density, the system will collapse. The integral of |V(x)| must also be finite for this condition to hold.

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Homework Statement


Homework Equations


(this is ~Fetter & Walecka Quantum theory of many-particle systems problem 1.2b)
Homogeneous system of spin 1/2 particles, potential V.
Expectation value of Hamiltonian in the non interacting ground state is
[tex]E^{(0)} + E^{(1)} = 2 \sum_k^{k_F} \frac{\hbar^2 k^2}{2m} + 1/2 \sum_{k \lambda}^{k_F} \sum_{k' \lambda'}^{k_F} \big[ <k\lambda k'\lambda'|V|k\lambda k'\lambda'> - <k\lambda k'\lambda'|V|k'\lambda' k\lambda>\big][/tex]

Assume V is central and spin independent
V(|x_1-x_2|) < 0 for all |x_1-x_2|
The intergral of |V(x)| is finite

Prove that the system will collapse.
Hint: start from [tex]( E^{(0)} + E^{(1)} ) / N[/tex] as a function of density

The Attempt at a Solution



If the energy per particle, [tex]( E^{(0)} + E^{(1)} ) / N[/tex], is reduced when the density increases (which I guess means that N increases) the system will collapse.
But how do I show that, I don't see what I can do.
 
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If the particle number increases, the sums might have a few more terms, how does that reduce the number of particles?
 

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