Quadratic Equation Calculus Proof

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SUMMARY

The discussion focuses on proving that the quadratic function f(x) = ax² + bx + c, where a > 0, satisfies f(x) ≥ 0 for all x if and only if the discriminant b² - 4ac ≤ 0. Participants confirmed that the minimum value occurs at x = -b/2a, derived from the derivative of f(x). The conversation highlights the importance of correctly substituting this value into the function to demonstrate the non-negativity of f(x).

PREREQUISITES
  • Understanding of quadratic functions and their properties
  • Knowledge of calculus, specifically derivatives
  • Familiarity with the concept of discriminants in quadratic equations
  • Ability to manipulate algebraic expressions
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  • Study the derivation of the vertex form of a quadratic function
  • Learn about the implications of the discriminant in quadratic equations
  • Explore optimization techniques in calculus
  • Review examples of quadratic inequalities and their solutions
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Students studying calculus, mathematicians interested in quadratic functions, and educators teaching algebra and calculus concepts.

harrietstowe
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Homework Statement


Consider the general quadratic function f(x)=ax2+bx+c with a>0. By calculating the minimum value of this function, show that f(x)\geq0 for all x if and only if b2-4ac\leq0


Homework Equations





The Attempt at a Solution


I know that the min for a quadratic equation is at x=-b/2a and I proved this by taking the derivative of f(x) and setting it equal to zero. I then plugged this in for x to get c+ax2 but I don't know where to go from there.
Thank You
 
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You plugged in x=-b/2a wrong... I mean, your formula still shows an x. That shouldn't be there...
 
Ahh now I see. Thank you
 

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