Quadratic Equations and kinetics

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mode656
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Homework Statement


Find the time required for a train to reach 100m if V0=20m/s and acceleration is
0.5m/s2


Homework Equations


s=v0t+(1/2)at2


The Attempt at a Solution


i am not sure of how to go about getting s=(20)t+(1/2)0.5t2 into quadratic form for use in the quadratic formula
this is my solution without the quad formula
s=v0t+(1/2)at2
100=(20)t+(1/2)0.5t2
5=t+(1/2)0.5t2
5=t+.25t2
5=t3
cube root of 5 is 1.71 which is def wrong:(
 
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mode656 said:
5=t+.25t2
5=t3
cube root of 5 is 1.71 which is def wrong:(

Just bring the '5' on the other side to get

0.25t2+t-5 = 0

at2+bt+c=0
 
in my book its sets up the quadratic form as t2+80t-400=0
the answer is still wrong i get 10??

it is supposed to be 4.5
 
[tex]\Delta[/tex]x=vit+[tex]\frac{1}{2}[/tex]at2

There's your kinematic equation.

Edit: sorry didn't see your attempt.

[tex]\Delta[/tex]x=vit+[tex]\frac{1}{2}[/tex]at2

0=vit+[tex]\frac{1}{2}[/tex]at2-[tex]\Delta[/tex]x

[tex]\frac{1}{2}[/tex]at2+vit-[tex]\Delta[/tex]x=0

Quadratic form
 
i know that's the equation but i need the quadratic formula to solve for time when only acceleration, distance and initial velocity is known
 
mode656 said:
i know that's the equation but i need the quadratic formula to solve for time when only acceleration, distance and initial velocity is known

Those are the only variables you need to know. I edited my above post, sorry for reposting what you knew.
 
don't worry about it. My problem does not lie within my use of the quadratic formula. My question is just pretty much how the book got t^2+80t-400=0
from 100=(20)t+(1/2)0.5t2
 
mode656 said:
don't worry about it. My problem does not lie within my use of the quadratic formula. My question is just pretty much how the book got t^2+80t-400=0
from 100=(20)t+(1/2)0.5t2

Multiply your equation throughout by 4.
 
any specific reason why? or is it just so?
 
mode656 said:
any specific reason why? or is it just so?

If you plan to manually factorize it, it is easier to find the factors.

So instead of factorizing (1/4)t2+20t-100=0, it is easier to factorize out t2+80t-400.

If you plan to use the quadratic equation formula, then it really does not matter what form you put it in.