Quadrature amplitude modulation

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Discussion Overview

The discussion revolves around the topic of Quadrature Amplitude Modulation (QAM) as part of a homework problem in Analog Signal Processing. Participants are tasked with finding the expression for the QAM signal and demonstrating how to extract the individual signals using synchronous detection.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant proposes an expression for the QAM signal as x_qam(t) = m1(t)cos(wp*t) + m2(t)sin(wp*t), but questions the role of the -Pi/2 phase shift.
  • Another participant suggests that the -Pi/2 phase shift converts cosine to sine, indicating a relationship between the two signals.
  • A third participant expresses uncertainty about the correctness of the initial expressions for m1(t) and m2(t) and asks for clarification on the functions represented by the X and Sigma elements in the provided scheme.
  • There is a mention of using low-pass filtering to eliminate high-frequency components, referencing trigonometric identities.

Areas of Agreement / Disagreement

Participants express differing views on the correctness of the initial expressions for m1(t) and m2(t), and there is no consensus on the complete formulation of the QAM signal. The discussion remains unresolved regarding the exact expressions and their implications.

Contextual Notes

Participants have not fully clarified the assumptions behind the expressions for m1(t) and m2(t), nor have they resolved the implications of the phase shifts and the roles of the X and Sigma elements in the modulation scheme.

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Homework Statement


The problem is about the http://en.wikipedia.org/wiki/Quadrature_amplitude_modulation" . This is a work from my course Analog signal processing.
Here is the scheme

http://img99.imageshack.us/img99/9449/zrgwj2.jpg

Two things to do :
1. Find the expression of x_qam(t)
2. Show that each of the signals m1(t) and m2(t) can be extract thanks to the synchronous detection using two local oscillators in quadrature (cf. scheme)2. The attempt at a solution
For the first question, I say :
m1(t)=cos(wp*t)
m2(t)=cos(wp*t-Pi/2)*sin(wp*t-Pi/2)
But I really doubt that is correct.

For the second question, I have no idea :(

As it is an work from my course "Analog signal processing", it should deal with transform Fourier and this kind of stuff but I really don't know how to start. It would be really great to have some help.
 
Last edited by a moderator:
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No, I don't think that's correct... what do the X elements do?
What does the Sigma element do?
 
mda said:
No, I don't think that's correct... what do the X elements do?
What does the Sigma element do?
X: multiplication
Sigma: addition

I think of that :
x_qam(t)=m1(t)*cos(wp*t)+m2(t)*sin(wp*t)

But what about the -Pi/2 ?
 
Last edited:
correct. -pi/2 is a phase shift from cos to sin.
 
xqam= m1(t)*cos(wp*t) + m2(t)*cos(wp*t)*sin(wp*t)

The -Pi/2 block converts the cos into a sine.

At the top before the LP filter you have m1(t)*cos^2(wp*t) + m2(t)*cos^2(wp*t)*sin(wp*t)

The LP filter drops the high frequency components using trig identities. See http://en.wikipedia.org/wiki/Quadrature_amplitude_modulation
 

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