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Calculating Quantum Defect for Na I 3p-nd, n=4-7 Terms
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[QUOTE="Philip Land, post: 6040832, member: 648831"] [h2]Homework Statement [/h2] The spectrum shows the series 3p - [I]n[/I]d, [I]n [/I]= 4 - 7 in Na as well as the resonance line 3s - 3p, with the experimental vacuum wavelengths in Å.Calculate the quantum defect for the nd ##^2D## [I]n [/I]= 4-7 terms. Estimate, as accurately as possible, the wavelength for 3p - 8d. The ionization energy in Na I is 41449.6 cm-1. Neglect all finestructure. [h2]Homework Equations[/h2] ##E_{ionization} - E_{excitation} = T = R\frac{(z-N_{inner})^2}{(n-\delta)^2}## [h2]The Attempt at a Solution[/h2] Hi! I can take the inverse of the given wavelength, to get T. ##\frac{1}{\lambda} = T##. Then I can plug this into the above equation and solve for delta. ##\delta = n - sqrt(\frac{R*(z-N_{inner})^2)}{T})## But my question is. Do I also need to take the quantum defect for p into account? Where my ##T = R*(z-N_{inner})^2 ( \frac{1}{(n-\delta_p)^2} - \frac{1}{(n-\delta_d)^2}) ## And if so, how would I get ##\delta_p##? If it was s, I could impy solve for ##delta_s## when putting ##T= E_{io}##. Figure attached[ATTACH=full]229292[/ATTACH] [/QUOTE]
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Calculating Quantum Defect for Na I 3p-nd, n=4-7 Terms
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