Quantum Mechanics Boundary conditions

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SUMMARY

The discussion focuses on boundary conditions in quantum mechanics, specifically addressing the matching of wave functions at the interface of two regions. The participants clarify that two separate wave functions, ##\psi_1## for ##x<0## and ##\psi_2## for ##x \ge 0##, should be considered. The expressions for these wave functions are given as ##\psi_1(x) = A e^{ikx} + Be^{-ikx}## and ##\psi_2(x) = C e^{iqx} + De^{-iqx}##. At the boundary, the condition ##\psi_1 = \psi_2## must be satisfied, which leads to the evaluation of both wave functions at ##x=0##.

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MaxJ
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Homework Statement
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Relevant Equations
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For this problem,
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The solution is,
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I have a doubt about Step number 3 about boundary conditions. Someone maybe be able to solve that doubt?

Kind wishes
 
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MaxJ said:
I have a doubt about Step number 3 about boundary conditions. Someone maybe be able to solve that doubt?
Not unless you tell us what your actual doubt is. The math is straightforward, essentially plug-and-chug.
 
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Orodruin said:
Not unless you tell us what your actual doubt is. The math is straightforward, essentially plug-and-chug.
Sir, bless you.

Doubt is matching wave functions give A + B = C + D and how they get their expression for derivatives (also in step 3).
 
MaxJ said:
Doubt is matching wave functions give A + B = C + D and how they get their expression for derivatives (also in step 3).
It would be more conventional (and clearer) to consider 2 separate wave-functions, one for each region: ##\psi_1## for ##x<0## and ##\psi_2## for ##x \ge 0##.

Each wave-function contains 2 terms, representing waves moving in the +x and -x directions in that region.

So, adapting your solution’s notation:
##\psi_1(x) = A e^{ikx} + Be^{-ikx}##
##\psi_2(x) = C e^{iqx} + De^{-iqx}##

At ##x=0## we require that ##\psi_1 =\psi_2##. Simply evaluate ##\psi_1##and ##\psi_2## at ##x=0## and equate them.

Similarly for the dervatives.
 
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