Quantum Mechanics Boundary conditions

AI Thread Summary
The discussion focuses on clarifying doubts regarding boundary conditions in quantum mechanics, specifically in Step 3 of a problem. Participants emphasize the importance of clearly stating the doubt to facilitate assistance. The solution involves using two separate wave functions for different regions, with each function representing waves in both directions. At the boundary, the wave functions must be equal, and this equality can be evaluated at the boundary point. The conversation highlights the necessity of matching both the wave functions and their derivatives at the boundary for a complete solution.
MaxJ
Messages
7
Reaction score
0
Homework Statement
below
Relevant Equations
below
For this problem,
1723530036965.png

The solution is,
1723530056524.png

1723530081396.png

1723530099482.png

1723530114429.png

I have a doubt about Step number 3 about boundary conditions. Someone maybe be able to solve that doubt?

Kind wishes
 
Physics news on Phys.org
MaxJ said:
I have a doubt about Step number 3 about boundary conditions. Someone maybe be able to solve that doubt?
Not unless you tell us what your actual doubt is. The math is straightforward, essentially plug-and-chug.
 
Orodruin said:
Not unless you tell us what your actual doubt is. The math is straightforward, essentially plug-and-chug.
Sir, bless you.

Doubt is matching wave functions give A + B = C + D and how they get their expression for derivatives (also in step 3).
 
MaxJ said:
Doubt is matching wave functions give A + B = C + D and how they get their expression for derivatives (also in step 3).
It would be more conventional (and clearer) to consider 2 separate wave-functions, one for each region: ##\psi_1## for ##x<0## and ##\psi_2## for ##x \ge 0##.

Each wave-function contains 2 terms, representing waves moving in the +x and -x directions in that region.

So, adapting your solution’s notation:
##\psi_1(x) = A e^{ikx} + Be^{-ikx}##
##\psi_2(x) = C e^{iqx} + De^{-iqx}##

At ##x=0## we require that ##\psi_1 =\psi_2##. Simply evaluate ##\psi_1##and ##\psi_2## at ##x=0## and equate them.

Similarly for the dervatives.
 
Last edited:
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top