Quaternions, how to prove q^** = q

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SUMMARY

The discussion focuses on proving that the double conjugate of a quaternion, denoted as (q*)*, equals the original quaternion q. The quaternion is defined as q = a + bi + cj + dk, where a, b, c, and d are real numbers. The solution involves applying the definition of the quaternion conjugate, resulting in (q*)* = (a - bi - cj - dk)* = a + bi + cj + dk, confirming that (q*)* indeed equals q.

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Homework Statement


quaternion q = a + bi + cj + dk
conjugate q* = a - bi - cj - dk

I do not know how I get (q*)* = q



The Attempt at a Solution

 
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a, b, c and d are real, aren't they? Just take the double conjugate.
 


a,b,c, and d are real.
so just..
show that (q*)* = q
(a + bi + cj + dk)* = a - bi - cj - dk and
(a - bi - cj - dk)* = a + bi + cj + dk Complete.
is it enough?
 


I can't think of anything I'd add.
 

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