How to derive Non-normalized quaternion with respect to time?

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SUMMARY

The derivative of a non-normalized quaternion, denoted as q, can be expressed using the formula $$\dot{q}=\left|q\right|\dot{\hat{q}}+\hat{q}\frac{d\left|q\right|}{dt}$$. This approach incorporates the time-dependent magnitude of the quaternion, |q|, and the normalized quaternion $$\hat{q}$$. The discussion highlights the complexity of deriving this expression, emphasizing that without additional constraints, the resulting expression remains general and arbitrary.

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Roni BM
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I know that for normalized quaternion, $$\hat{q}$$, the derivative is given by $$\frac{d\hat{q}}{dt}=\frac{1}{2}\hat{q}\cdot \omega$$ where $$\cdot$$ denotes the quaternion multiplication.

I want to calculate the time derivative of a non-normalized quaternion q.

I tried to calculate the derivative by using the chain rule, $$\dot{q}=\left|q\right|\dot{\hat{q}}+\hat{q}\frac{d\left|q\right|}{dt}$$ and I got a very complicated term. I wonder if I am having a wrong approach and if there is a known formula?
 
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I assume you have a time dependent radius ##|q|##, which means you have an arbitrary path in a four dimensional real space. So without any further information, the expression is necessarily general and arbitrary.
 

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