How to derive Non-normalized quaternion with respect to time?

  • #1
Roni BM
1
0
I know that for normalized quaternion, $$\hat{q}$$, the derivative is given by $$\frac{d\hat{q}}{dt}=\frac{1}{2}\hat{q}\cdot \omega$$ where $$\cdot$$ denotes the quaternion multiplication.

I want to calculate the time derivative of a non-normalized quaternion q.

I tried to calculate the derivative by using the chain rule, $$\dot{q}=\left|q\right|\dot{\hat{q}}+\hat{q}\frac{d\left|q\right|}{dt}$$ and I got a very complicated term. I wonder if I am having a wrong approach and if there is a known formula?
 

Answers and Replies

  • #2
fresh_42
Mentor
Insights Author
2022 Award
17,813
19,030
I assume you have a time dependent radius ##|q|##, which means you have an arbitrary path in a four dimensional real space. So without any further information, the expression is necessarily general and arbitrary.
 

Suggested for: How to derive Non-normalized quaternion with respect to time?

Replies
3
Views
234
Replies
7
Views
2K
Replies
3
Views
141
Replies
2
Views
6K
  • Last Post
Replies
7
Views
2K
Replies
10
Views
845
Replies
15
Views
751
Replies
2
Views
695
Replies
5
Views
701
Top