Question about Applying V^2/r with two different velocities

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SUMMARY

The discussion centers on applying the equation V^2/r = -1g to determine the velocity required for a centripetal force scenario resulting in -1g acceleration. The user correctly identifies that the final velocity at the bottom of the arc should be used in the equation. This approach confirms that the final velocity squared divided by the radius equals -1g, establishing a clear method for solving centripetal force problems in a vertical turn context.

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  • Understanding of centripetal force and acceleration concepts
  • Familiarity with the equation V^2/r = -1g
  • Knowledge of final velocity in motion along a curved path
  • Basic principles of physics related to motion and forces
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  • Study the derivation and applications of centripetal acceleration formulas
  • Learn about the effects of varying radius on centripetal force
  • Explore real-world examples of centripetal force in automotive dynamics
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Students studying physics, particularly those focusing on mechanics and centripetal motion, as well as educators looking for practical examples of applying theoretical concepts in real-world scenarios.

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[SOLVED] Question about Applying V^2/r with two different velocities

Homework Statement


I have a problem where I am using the equation V^2/r = -1g to a problem with centripetal force. Basically the question is designing my own situation where i need to have a -1g acceleration on a turn and i decided on the picture below. It is a vertical picture.

Homework Equations


-1g = v^2/r

The Attempt at a Solution



drawing.jpg


I tried figuring out exactly how to get the velocity but I just don't seem to see which velocity to use.
 
Last edited:
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I know that the equation is V^2/r = -1g. I think the velocity I need to use is the final velocity, which is the velocity at the end of the arc, right? So in this case it would be the velocity of the car at the bottom after it has gone around the arc. So if I use the final velocity, the equation will be: Final Velocity^2/Radius = -1g Is this correct?
 

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