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Question about Average Velocities, vectors, kinematics

  1. Oct 11, 2008 #1
    1. In getting to his destination, a hill walker walks with an average velocity of 1.22 m/s due west. This is because he walks 6.38 km with an average velocity of 2.81 m/s due west, turns around 180 degrees and walks with an average velocity of 0.327 m/s due east. How far east did she walk (in km)



    2. Vector addition/ subtraction



    2.81 - 0.327 = 2.483
    2.81 = 6,380
    1 = 2270.46
    2.483 = 5637.56


    6380 - 5637.56 = 742.44

    Can someone please confirm if this is right ?

     
  2. jcsd
  3. Oct 11, 2008 #2

    Redbelly98

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    Welcome to PF.

    It's unclear what you are trying to write, because you have left out units. Saying 2.81=6,380 is just plain false, it's like saying 1=2.

    For example:
    1 inch = 2.54 cm is a correct statement
    1 = 2.54 is a false statement

    If you were to include units in your equations, it might be clearer just what you're trying to say.
     
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