Question about Average Velocities, vectors, kinematics

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SUMMARY

The discussion revolves around a hill walker who travels with an average velocity of 1.22 m/s due west after initially walking 6.38 km at 2.81 m/s due west and then turning around to walk back at 0.327 m/s due east. The calculations presented involve vector addition and subtraction to determine the distance walked east. The final distance walked east is confirmed to be approximately 0.742 km. Clarity in unit representation is emphasized for accurate communication of the calculations.

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1. In getting to his destination, a hill walker walks with an average velocity of 1.22 m/s due west. This is because he walks 6.38 km with an average velocity of 2.81 m/s due west, turns around 180 degrees and walks with an average velocity of 0.327 m/s due east. How far east did she walk (in km)



2. Vector addition/ subtraction



2.81 - 0.327 = 2.483
2.81 = 6,380
1 = 2270.46
2.483 = 5637.56


6380 - 5637.56 = 742.44

Can someone please confirm if this is right ?

 
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Welcome to PF.

It's unclear what you are trying to write, because you have left out units. Saying 2.81=6,380 is just plain false, it's like saying 1=2.

For example:
1 inch = 2.54 cm is a correct statement
1 = 2.54 is a false statement

If you were to include units in your equations, it might be clearer just what you're trying to say.
 

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