Question about calculating a spring's extension

  • Thread starter Thread starter Physics_Beginner300
  • Start date Start date
  • Tags Tags
    Extension
Click For Summary
SUMMARY

The discussion centers on calculating the compression of a spring when a 1.5 kg shotput with a velocity of 3.0 m/s lands on it. The spring constant (k) is given as 700 N/m. To find the compression (x), participants suggest using the kinetic energy (Ek) of the shotput and the work-energy principle, specifically the equation W = 1/2 k x^2. Additionally, gravitational potential energy (Ep) may need to be considered if the shotput falls vertically.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with kinetic and potential energy equations
  • Knowledge of spring mechanics and Hooke's Law
  • Basic algebra for solving equations
NEXT STEPS
  • Study the work-energy principle in physics
  • Learn about Hooke's Law and its applications in spring mechanics
  • Explore gravitational potential energy calculations
  • Investigate the effects of different spring constants on compression
USEFUL FOR

Students in physics, engineers working with mechanical systems, and anyone interested in understanding the dynamics of springs and energy transfer in collisions.

Physics_Beginner300
Messages
1
Reaction score
0
Homework Statement
A 1.5kg shotput has a velocity of 3.0 m/s and lands on a spring just before contact. The value of k, the spring constant, is 700 N m (Newton metres). Find how far the spring is compressed.
Relevant Equations
F = k(-x)
W (on mass) = Δ Ek
Δ Ek = 1/2 m v^2 - 1/2 m i^2 (v = final velocity and i = inital velocity)
Ep = mgh
W = 1/2 k x^2, where k = spring constant and x= extension of the spring
Hey guys, I think that the answer to this question is to solve for the amount of kinetic energy that the ball exerts on the spring, and the substitute that value to solve for x. However, I am not sure and quite stuck on how to start
 
Physics news on Phys.org
Physics_Beginner300 said:
Problem Statement: A 1.5kg shotput has a velocity of 3.0 m/s and lands on a spring just before contact. The value of k, the spring constant, is 700 N m (Newton metres). Find how far the spring is compressed.
Relevant Equations: F = k(-x)
W (on mass) = Δ Ek
Δ Ek = 1/2 m v^2 - 1/2 m i^2 (v = final velocity and i = inital velocity)
Ep = mgh
W = 1/2 k x^2, where k = spring constant and x= extension of the spring

Hey guys, I think that the answer to this question is to solve for the amount of kinetic energy that the ball exerts on the spring, and the substitute that value to solve for x. However, I am not sure and quite stuck on how to start
It's not clear what's stopping you. In any case, you have to make a serious attempt first before we can help you.

Ps it's a "shot". The "put" is the style of throw.
 
Physics_Beginner300 said:
velocity of 3.0 m/s
Direction unspecified? That's awkward. Looks like you'll have to assume it is collinear with the spring.
Physics_Beginner300 said:
solve for the amount of kinetic energy that the ball exerts on the spring, and the substitute that value to solve for x
To be precise, you would also need to take into account gravitational PE change during compression, but for that you would need to assume further that the ball fell vertically, which would not be a successful put.
 

Similar threads

Replies
18
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
Replies
16
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
Replies
24
Views
4K
  • · Replies 58 ·
2
Replies
58
Views
3K
Replies
17
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
29
Views
3K