- #1
7thSon
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Suppose I have a smooth scalar function f defined on some region in the x-y plane. Its partial derivatives with respect to x and y are well-defined.
Someone explain this "proof" to me that the quantity:
[tex] \frac{dx}{df} = \frac{f_{,x}}{f_{,x}^2 + f_{,y}^2} [/tex] (similar expression for dy/df)
The authors from which I read this do this by taking the the total differential of f
[itex] df = \frac{\partial f}{\partial x} dx + \frac{\partial f}{\partial y} dy [/itex]
dividing both sides by dx:
[itex] \frac{df}{dx} = frac{\partial f}{\partial x} + \frac{\partial f}{\partial y} \frac{dy}{dx} [/itex]
and substituting in the relation
[tex] \frac{dy}{dx} = \frac{f_{,y}}{f_{,x}} [/tex]
which gives you the resulting expression.
I would be fine with this if they substituted in the normal result of the implicit function theorem, which gives you, for a level set of f,
[tex] \frac{dy}{dx} = - \frac{f_{,x}}{f_{,y}} [/tex]
However, it seems like since they decided they were more interested in the normal to the level set, rather than the tangent to the level set, they substituted in the different value of dy/dx! Why are they allowed to substitute in a different value for dy/dx, or is there something that I'm missing?
Another thing I was thinking was maybe there is a dual to the idea of the dot product of grad f with a tangent vector? But instead, between a total differential and a covector [dx,dy]? Is that why they can use an expression for dy/dx that is not the tangent to the level curve?
Someone explain this "proof" to me that the quantity:
[tex] \frac{dx}{df} = \frac{f_{,x}}{f_{,x}^2 + f_{,y}^2} [/tex] (similar expression for dy/df)
The authors from which I read this do this by taking the the total differential of f
[itex] df = \frac{\partial f}{\partial x} dx + \frac{\partial f}{\partial y} dy [/itex]
dividing both sides by dx:
[itex] \frac{df}{dx} = frac{\partial f}{\partial x} + \frac{\partial f}{\partial y} \frac{dy}{dx} [/itex]
and substituting in the relation
[tex] \frac{dy}{dx} = \frac{f_{,y}}{f_{,x}} [/tex]
which gives you the resulting expression.
I would be fine with this if they substituted in the normal result of the implicit function theorem, which gives you, for a level set of f,
[tex] \frac{dy}{dx} = - \frac{f_{,x}}{f_{,y}} [/tex]
However, it seems like since they decided they were more interested in the normal to the level set, rather than the tangent to the level set, they substituted in the different value of dy/dx! Why are they allowed to substitute in a different value for dy/dx, or is there something that I'm missing?
Another thing I was thinking was maybe there is a dual to the idea of the dot product of grad f with a tangent vector? But instead, between a total differential and a covector [dx,dy]? Is that why they can use an expression for dy/dx that is not the tangent to the level curve?
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