Question about impulse forces and tipping point of block

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SUMMARY

The discussion centers on the dynamics of tipping points for a block subjected to impulse forces. The equation for tipping, defined as umg=mgL/2h, applies under conditions of equilibrium. However, when an impulse force is applied, such as a quick strike, the tipping point is significantly altered due to the lack of equilibrium during the impact. This phenomenon indicates that impulse forces can lower the tipping point compared to static forces.

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johnnnnyyy
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Sorry if I am posting this in the wrong place but this is my first post.

I know the equation for tipping of a block when force is slowly added until it either tips of slides is umg=mgL/2h but I have noticed that when you quickly strike the block with your finger, the point at where the block tips becomes much lower. Does anybody know why this is or know what the equation is that explains this?


Thanks!
 
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The equation you provided assumes equilibrium. If you strike the block quickly, the block will not be at equilibrium.
 

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