Question about making vectors equilibrium

Click For Summary
SUMMARY

The discussion centers on calculating the third force required for equilibrium when two forces of equal magnitude (4.6 N) act at an angle of 40° to each other. The participant initially calculated a force of 4.3 N directed opposite to the resultant of the two forces but was advised to refine their approach using vector addition principles. The correct method involves applying the equilibrium condition, which states that the sum of all forces must equal zero, leading to the equation \(\vec{F}_1 + \vec{F}_2 + \vec{F}_3 = 0\). This allows for the determination of the magnitude and direction of the third force.

PREREQUISITES
  • Understanding of vector addition and equilibrium principles
  • Knowledge of trigonometric functions, specifically cosine
  • Familiarity with Newton's laws of motion
  • Basic skills in solving algebraic equations
NEXT STEPS
  • Study vector resolution techniques in physics
  • Learn about equilibrium conditions in static systems
  • Explore the application of trigonometric identities in force calculations
  • Practice solving problems involving multiple forces and their resultant
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and force equilibrium, as well as educators seeking to clarify concepts related to vector forces and equilibrium conditions.

preluderacer
Messages
83
Reaction score
0

Homework Statement



The figure shows two forces of equal magnitude acting on an object. If the common magnitude of the forces is 4.6 N and the angle between them is 40°, what third force will cause the object to be in equilibrium?


The Attempt at a Solution




What I did was split them down the middle, then used 4.6cos(40) degrees and then got 4.3N I just pointed it in the opposite direction to make it equilibrium. Does this sound like the correct method to use?
 
Physics news on Phys.org
What is the definition of equilibrium? What does equilibrium mean for the sum of forces on the object?
 
It means they are balanced right? I thought by pointing the vector in the opposite direction balances it.
 
"Pointing the vector in the opposite direction" is the right idea, but we need to be more mathematically precise than that to solve the problem.

Equilibrium means that the object doesn't move. What does that say about the acceleration of the object? What does that imply about the sum of forces on the object?
 
The original opened up leftward. I messed up when stating it. When I split them i also split the degrees so I used 4.6Ncos(20) degrees. I wound up with 4.3 N pointed toward the left My logic is that it has to be pointed to the right to balance out the forces to make them zero. Is 4.3N the right magnitude of the 2 velocities?
 
From what you describe, you have the direction of the 3rd vector correct. If you'd answer my questions from post #4, you'd have a strong hint about how to compute the magnitude of the force.
 
It means the acceleration is zero. I am so confused are u implying that my magnitude is wrong?
 
preluderacer said:
It means the acceleration is zero. I am so confused are u implying that my magnitude is wrong?

I'm just trying to explain to you how to verify whether your magnitude is correct. If the original 2 vectors were more complicated, your method would not have worked.

If the acceleration is zero, what does that imply about the sum of all of the forces? Rearranging the sum will give you a relationship between the 3rd force and the other two. This will let you compute the magnitude of the 3rd force.
 
The sum of forces are zero
 
  • #10
Can you write an expression for the 3rd force in terms of the first two? How about computing the magnitude of the 3rd force from that?
 
  • #11
You're losing me =( sorry. Iam so confused now.
 
  • #12
\vec{F}_1+\vec{F}_2+\vec{F}_3=0,

can you solve this for \vec{F}_3? Then compute |\vec{F}_3|.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
1K
Replies
14
Views
2K
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K